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VLD [36.1K]
3 years ago
11

A moon with a mass of 6.0 x 10 kg orbits about a planet with a mass of 5.0x 10^24 kg. They are 4.0 x 10^8 meters apart What is t

he gravitational force between them? The answer is 1.25 x 10^20 N, it won’t let me answer my own question so someone put that as the answer!
Physics
1 answer:
allochka39001 [22]3 years ago
4 0

The gravitational force between them is <em>1.25 x 10^20 Newtons.</em>

(I think you must have typed the mass of the moon wrong.  

It must be 6.0 x 10^22 kg.)

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Two rockets are flying in the same direction and are side by side at the instant their retrorockets fire. Rocket A has an initia
lara31 [8.8K]

Answer:

-22.2 m/s²

Explanation:

The equation for position x for a constant acceleration a, time t and initial velocity v₀, initial position x₀:

(1) x=\frac{1}{2}at^2+v_0t+x_0

For rocket A the initial and final position: x = x₀= 0. Using these values in equation 1 gives:

(2) 0=\frac{1}{2}at^2+v_0t

Solving for time t:

-\frac{1}{2}at^2=v_0t

(3) t=-\frac{2v_0}{a}

The times for both rockets must be equal, since they start and end at the same location. Using equation 3 for rocket A and B gives:

(4) \frac{v_{0A}}{a_A}=\frac{v_{0B}}{a_B}

Solving equation 4 for acceleration of rocket B:

(5) a_B=a_A\frac{v_{0B}}{v_{0A}}

3 0
3 years ago
A 0.37-kg object connected to a light spring with a force constant of 23.2 N/m oscillates on a frictionless horizontal surface.
mars1129 [50]

Answer:

a) v = 31.67 cm / s , b)   v = -29.36 cm / s , c) v= 29.36 cm/s, d) x = 3.46 cm

Explanation:

The angular velocity in a simple harmonic movement is

       w = √ K / m

       w = √ 23.2 / 0.37

       w = 7,918 rad / s

a) the expression against the movement is

        x = A cos (wt + Ф)

Speed ​​is

        v = dx / dt = - A w sin (wt + Ф)

 The maximum speed occurs for cos = ± 1

        v = A w

        v = 4.0 7,918

        v = 31.67 cm / s

b) as the object is released from rest

        0 = -A w sin (0+ Фi)

        sin Ф = 0

         Ф = 0

The equation is

        x = 4.0 cos (7,918 t)

        v = -4.0 7,918 sin (7,918 t)

        v = - 31.67 sin (7.918t)

     

Let's look for the time for a displacement of x = 1.5 cm, remember that the angles must be in radians

          7,918 t = cos⁻¹ 1.5 / 4.0

          t = 1,186 / 7,918

          t = 0.1498 s

We look for speed

         v = -31.67 sin (7,918 0.1498)

         v = -29.36 cm / s

c) if the object passes the equilibrium equilibrium position again at this point the velocity has the same module, but the opposite sign

         v = 29.36 cm / s

d) let's look for the time for the condition v = v_max / 2

         31.67 / 2 = 31.67 sin ( 7,918 t)

          7.918t = sin⁻¹ 0.5

         t = 0.5236 / 7.918

         t = 0.06613

With this time let's look for displacement

         x = 4.0 cos (7,918 0.06613)

        x = 3.46 cm

6 0
3 years ago
A student who weighs 500 newtons climbed the stairs from the first floor to the third floor,15 meters above, in 20 seconds. How
damaskus [11]
Work = (500N)(15m)=7500J Power= (7500J)/(20s) =375 W
Hopefully this helps
3 0
3 years ago
Two water balloons of mass 0.75 kg collide and bounce off of each other without breaking. Before the collision, one water balloo
bagirrra123 [75]
By the law of momentum conservation:-
=>m¹u¹ + m²u² = m1v1 + m²v² {let East is +ve}
=>u¹ + u² = v¹ + v² {as m1=m2}
=>3.5 - 2.75 = v1-1.5
<span> =>v¹ = 2.25 m/s (East) </span>
5 0
3 years ago
Opal adds 25 grams of salt to a one-liter glass beaker filled up to its volume mark with pure water. She stirs the water until t
Mars2501 [29]

By what i know i think that the answer would be A a homogeneous mixture.

5 0
3 years ago
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