Given an ion with a charge of +4, how many ions with a charge of -2 will be necessary to create a stable compound? Explain.
1 answer:
Answer:
Explanation:
A stable compound has a net charge of 0. Basically, when added, the two ion charges must equal 0 and balance each other out.
We have one ion with a charge of +4. There is another ion of -2. Clearly, these are not balanced yet.
We need more -2 ions to balance it. If we have 2 ions, then their charge is -4 because:
- 2 * -2 charge = -4 charge
The +4 ion and 2 -2 ions (with a charge of -4) balance each other out and create a net charge of 0. So, <u>2 ions with a charge of -2</u> are necessary to create a stable compound.
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Answer:
Here's what I get
Explanation:
(a) Intermediates
The three structures below represent one contributor to the resonance-stabilized intermediate, in which the lone pair electrons on the heteroatom are participating (the + charge on the heteroatoms do not show up very well).
(b) Relative Stabilities
The relative stabilities decrease in the order shown.
N is more basic than O, so NH₂ is the best electron donating group (EDG) and will best stabilize the positive charge in the ring. However, the lone pair electrons on the N in acetanilide are also involved in resonance with the carbonyl group, so they are not as available for stabilization of the ring.
(c) Relative reactivities
The relative reactivities would be
C₆H₅-NH₂ > C₆H₅-OCH₃ > C₆H₅-NHCOCH₃
