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Nadya [2.5K]
3 years ago
15

a car moving on a road passes by kilometer 218 at 10:15 am and milestone 236 at 10:30 am. determine an average scalar speed in k

m / h over this stretch.
Physics
1 answer:
Leno4ka [110]3 years ago
5 0

Answer:

v?

Explanation:

v = ∆s / ∆t

v =?

∆s = 236 - 218 = 18km

=t = 10: 30 - 10:15 = 15 minutes to hour 15/60 = 0.25h

v = 18 / 0.25

v = 72km / h

speed of 72km / h

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Equilibrium price will fall and quantity demanded for jelly will also fall

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Peanut butter and jelly are consumed together. It means they are complementary goods. These are those goods which are bought together. So increase or decrease in the price of one commodity will automatically affect the demand for another commodity.

When the price of peanut butter increases than people will demand less of peanut butter. Similarly, the demand for jelly is associated directly with the demand for peanut butter. So it will also fall . Due to the fall in the price of jelly and simultaneous fall in demand, the equilibrium price will fall.

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A book weighing 12 n is placed on a table. how much support force does a table exert on the book?
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It should be 12 N. the force of the book on the table should be the same as the force of the table on the book.
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Which refers to the amount of heat required to change the temperature of 1 gram of a substance by 1°C and is related to the chem
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Specific heat

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<h3>What is galvanic cell?</h3>
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1 year ago
A weight of 30.0 N is suspended from a spring that has a force constant of 220 N/m. The system is undamped and is subjected to a
Nimfa-mama [501]

Answer:

F_0 = 393 N

Explanation:

As we know that amplitude of forced oscillation is given as

A = \frac{F_0}{ m(\omega^2 - \omega_0^2)}

here we know that natural frequency of the oscillation is given as

\omega_0 = \sqrt{\frac{k}{m}}

here mass of the object is given as

m = \frac{W}{g}

\omega_0 = \sqrt{\frac{220}{\frac{30}{9.81}}}

\omega_0 = 8.48 rad/s

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now we have

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F_0 = 393 N

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3 years ago
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