First:
5 cm = 0,05 m
Now, the formula:
F = k * (qq') / r²
Replacing:
F = 9x10⁹ * (55x10⁸ * 1x10⁷) / 0,05²
F = 9x10⁹ * (5,5x10¹⁶ / 2,5x10⁻³)
F = 9x10⁹ * 2,2x10¹⁹
F = 1,98x10²⁹
The force between the charges is 1,98x10²⁹ Newtons.
First figure shows the object position
Second shows the image position
Third shows the focal length.
The atoms furthest from the nucleus
Answer: 6.47m/s
Explanation:
The tangential speed can be defined in terms of linear speed. The linear speed is the distance traveled with respect to time taken. The tangential speed is basically, the linear speed across a circular path.
The time taken for 1 revolution is, 1/3.33 = 0.30s
velocity of the wheel = d/t
Since d is not given, we find d by using formula for the circumference of a circle. 2πr. Thus, V = 2πr/t
V = 2π * 0.309 / 0.3
V = 1.94/0.3
V = 6.47m/s
The tangential speed of the tack is 6.47m/s
