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stiks02 [169]
3 years ago
5

At full power, how long would it take for the car to accelerate from 0 to 62.0 mph ? neglect friction and air resistance.

Physics
1 answer:
Luba_88 [7]3 years ago
7 0
Given that At full power, the same car can accelerate from 0 to 31 mph in time 1.5 s. How long would it take for the car to accelerate from 0 to 62.0 mph. 
Energy= integral (P×dt) = Pt
therefore;
Since kinetic energy = 1/2 mv^2 = Pt
1/2m(31)² = 1.5 P
  480.5 m  = 1.5 P
        P = 320.33 m
Using the other scenario
1/2m(62)² = 320.33mt
    = 1922 m =320.33 mt
           t = 6.0 sec
 

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3 years ago
At a time t = 2.80 s , a point on the rim of a wheel with a radius of 0.230 m has a tangential speed of 51.0 m/s as the wheel sl
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Answer:

Part A) the angular acceleration is α= 44.347 rad/s²

Part B) the angular velocity is 195.13 rad/s

Part C)  the angular velocity is 345.913 rad/s

Part D ) the time is t= 7.652 s

Explanation:

Part A) since angular acceleration is related with angular acceleration through:

α = a/R = 10.2 m/s² / 0.23 m =   44.347 rad/s²

Part B) since angular acceleration is related

since

v = v0 + a*(t-t0) =  51.0 m/s + (-10.2 m/s²)*(3.4 s - 2.8 s) = 44.88 m/s

since

ω = v/R = 44.88 m/s/ 0.230 m = 195.13 rad/s

Part C) at t=0

v = v0 + a*(t-t0) =  51.0 m/s + (-10.2 m/s²)*(0 s - 2.8 s) = 79.56 m/s

ω = v/R = 79.56 m/s/ 0.230 m = 345.913 rad/s

Part D ) since the radial acceleration is related with the velocity through

ar = v² / R → v= √(R * ar) = √(0.23 m  * 9.81 m/s²)= 1.5 m/s

therefore

v = v0 + a*(t-t0) → t =(v -  v0) /a + t0 = ( 1.5 m/s - 51.0 m/s) / (-10.2 m/s²) + 2.8 s = 7.652 s

t= 7.652 s

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3 years ago
Predict which atom has the higher ionization energy. Na Al
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3 years ago
Express 79 m in units of (a) centimeters
dem82 [27]

Answer: a) 7,00 centimeters

(b) 259. 19 feet

(c) 3110.28 inches

(d) 0.049 miles

Explanation:

(a) We know that 1 meter = 100 centimeters

Therefore,

79\ m= 7,900\text{ centimeters}

(b)Since 1 meter = 3.28084 feet

Then, 79\ m= 79\times3.28084=259.18636\approx 259.19\text{ feet}

(c) Since, 1 feet = 12 inches.

79\ m=259.19\text{ feet}=259.19\times12=3110.28\text{ inches}

(d) \text{Since 1 feet= }\dfrac{1}{5280}\text{ mile}

79\ m=259.19\text{ feet}=\dfrac{259.19}{5280}= 0.0490890151515\approx0.049\text{ miles}

8 0
4 years ago
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