Answer:
Explanation:
electrical field strength = potential diff / distance
= ( 450 - 0 ) / 8 x 10⁻²
= 5625 V/m
b )
potential difference = electric field x distance
= 5625 x .10
= 562.5 V
Answer:
Fusion
Fission
Explanation:
The first problem describes a nuclear fusion process. In this process;
- small atomic nuclei combines to form a larger one.
- it is accompanied by a large release of energy
- this energy provides the needed temperature to set up another light nuclei to fuse.
The second problem describes nuclear fission,
- a heavy nuclide is bombarded with a neutron.
- the product formed becomes unstable and subsequently breaks down.
- This leads to a series of chain reactions until stability is attained.
Charge dQ on a shell thickness dr is given by
dQ = (charge density) × (surface area) × dr
dQ = ρ(r)4πr²dr
∫ dQ = ∫ (a/r)4πr²dr
∫ dQ = 4πa ∫ rdr
Q(r) = 2πar² - 2πa0²
Q = 2πar² (= total charge bound by a spherical surface of radius r)
Gauss's Law states:
(Flux out of surface) = (charge bound by surface)/ε۪
(Surface area of sphere) × E = Q/ε۪
4πr²E = 2πar²/ε۪
<span>E = a/2ε۪
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It is due to the plurality of forces enacted on them. For example a bullet, if fired from a firearm, will move forward due to force from the gun, will slow down due to drag from air resistance, and will move downwards due to gravitational force. All these forces culminate in a parabolic (curved) path.