In order to determine the formula of the hydrate, [Anhydrous Solid⋅xH2O], the number of moles of water per mole of anhydrous solid (x) will be calculated by dividing the number of moles of water by the number of moles of the anhydrous solid (Equation 2.12.
Answer:
Nitrate NO3
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Explanation:
Lone pairs are present on nitrogen atoms of both pyridine and pyrrole.
In pyrrole, the electron pair on nitrogen is involved in resonance and hence does not available for bonding. Therefore, pyrrole does not possess basic character and remains unreactive towards HCl.
In case of pyridine, as 6 pi electrons are present in the ring, so, electron pair of nitrogen does not participate in resonance. So, because of presence of lone pair, pyridine possess basic character and hence, reacts readily reacts with HCl.
A nucleus of uranium 238 decays by alpha emission to form a daughter nucleus, thorium 234.
<h3>What are isotopes?</h3>
Isotopes are atoms with the same number of protons but differ in numbers of neutrons.
Uranium-238 produces thorium-234 by alpha decay.
An α-particle is a helium nucleus. It contains 2 protons and 2 neutrons, for a mass number of 4.
During α-decay, an atomic nucleus emits an alpha particle. It transforms (or decays) into an atom with an atomic number 2 less and a mass number 4 less.
Thus, uranium-238 decays through α-particle emission to form thorium-234 according to the equation:

Learn more about the isotopes here:
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Answer:
mercury, magnesium, water and gasoline.
Explanation:
Density:
Density is equal to the mass of substance divided by its volume.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
The liquid with higher density will sink in bottom while the liquid with lower density will float.
In given samples,
density of water = 1 g/mL
density of mercury = 13.6 g/mL
density of gasoline = 0.70 g/mL
density of magnesium = 1.7 g/mL
So on the basis of given density values mercury will sink in bottom then above it magnesium will present than water and above on these three gasoline will present.