1.5x10
=15N
sorry if im wrong
Answer:
2.5 moles of KOOH are produced.
Explanation:
1)Given data:
Number of moles of KOOH produced = ?
Number of moles of LiClO = 5 mol
Solution:
Chemical equation:
2LiClO + KHSO₄ → Li₂SO₄ + Cl₂ + KOOH
now we will compare the moles of KOOH and LiClO.
LiClO : KOOH
2 : 1
5 : 1/2×5 = 2.5
2.5 moles of KOOH are produced.
Answer: 2 grams
Explanation:
chemical formula of C6H:
C6H
relative atomic mass of
C:12
H:1
C6:72
H1:12
relative formula mass of
C6H1=73
molar mass of glucose:
73g
the molar mass is the mass of one mole of a substance.
in
26.2g
of C6H there are
26.2 divide by 73g moles present.
there are 0.358 or 35.8*10-1
I gram of NH3 is 17.03052
2 grams of NH3 is 35
Answer: d) 164.9 g
Explanation:
To calculate the moles :
The balanced chemical reaction is:
According to stoichiometry :
2 moles of 
require = 25 moles of 
Thus 0.412 moles of will require=
of
Mass of 
Thus 164.9 g of oxygen is consumed.
