Answer:
Coordinate
Explanation:
It comes in a set of values (x,y) in two dimensions or (x,y,z) in three dimensions. Coordinates are useful in many applications such as tracking planes in the air and also in the military in precision strikes. GPS also used coordinates to describe the location of a particular feature.
First, it is important to list the molar mass of the relevant substances.
Molar mass of magnesium = 24.305 g/mol
Molar mass of water = 18.0153 g/mol
Molar mass of H2 = 2.0159 g/mol
Second, we need to determine the limiting reactant for the chemical reaction. We take 4.73 g of Mg and determine the stoichiometric amount of water needed for it to be completely consumed. This is shown in the following equation:
4.73 g Mg x mol Mg/24.305 g x 2 mol H2O/1 mol Mg x 18.0153 g/mol H2O = 7.0119 g H2O
Thus, we have determined that 7.0119 g H2O is needed to completely react 4.73 g Mg. The given amount of 1.83 g H2O is insufficient which then indicates that water is the limiting reactant and should be the basis of our calculations.
Next, given 1.83 g H20, we calculate the theoretical yield of hydrogen gas using stoichiometry. The equation is then:
1.83 g H2O x mol H20/18.0153 g x 1 mol H2/2 mol H2O x 2.0159 g/mol H2 = 0.1024 g H2
However, the reaction yield was given to be 94.4%. The reaction yield is given by the formula percent yield = actual yield/ theoretical yield x 100%. Thus, the actual yield of hydrogen gas can be determined using the formula.
Actual yield of H2 = 0.94*0.1024 g H2
Thus, the amount of hydrogen gas produced is 0.0963 g.
Answer: In joules, Q = (47 kcal) (4186J/kcal) = 197 kJ. Since 47 kcal is released in the burning of 10 g of cookie, a 100-g portion would contain 470 food Calories, or 1970 kJ.
Missing question: volume of <span>solution on the left is 10 mL.
V</span>₁(solution) = 10 Ml.
c₁(solution) = 0.2 M.<span>
V</span>₂(solution)
= ?.<span>
c</span>₂(solution)
= 0.04 M.<span>
c</span>₁ -
original concentration of the solution, before it gets diluted.<span>
c</span>₂
- final concentration of the solution, after dilution.<span>
V</span>₁
- <span>volume to
be diluted.
V</span>₂ - <span>final volume after
dilution.
c</span>₁ · V₁ = c₂ · V₂<span>.
</span>10 mL · 0.2 M = 0.04 M · V₂.
V₂(solution) = 10 mL · 0.2 M ÷ 0.04 M.
V₂(solution) = 50 mL.<span>
</span>