Answer:
The mass of C2H2 in the mixture is 0.56gram using the ratio of carbon in the products contributed by the C2H2.
Explanation:
The balanced equation for the reaction is: C3H8 + 2C2H2 + 10O2 >> 7CO2 + 6H2O.
From the reaction, we know that the oxygen was in excess, this will make the Carbon sources the limiting agents in the reaction. The details of the reaction showed that the ratio of water to the carbon dioxide is 1.6:1. This also means that the expected mole of carbon dioxide will be 7/1.6, which is 3.75moles.
The individual balanced equation of reaction is:
C3H3 +5O2 >> 3CO2 + 4H2O
and 2C2H2 + 5O2 >>4CO2 + 2H2O. From this one can quickly tell that the propane is in sufficient supply as it produces 3 moles of CO2 out of the expected 3.75 moles obtained above. Leaving 0.75moles of CO2 to the ethyne.
The mass of ethyne in the mixture will therefore be: 0.75/3.75 X 2.8 = 0.56g.
That there are empty space in the atom
That almost all of the mass is concentrated at the center of the atom
Answer:
429.4 kJ are absorbed in the endothermic reaction.
Explanation:
The balanced chemical equation tells us that 1168 kJ of heat are absorbed in the reaction when 4 mol of NH₃ (g) react with 5 mol O₂ (g).
So what we need is to calculates how many moles represent 25 g NH₃(g) and calculate the heat absorbed. (NH₃ is the limiting reagent)
Molar Mass NH₃ = 17.03 g/mol
mol NH₃ = 25.00 g/ 17.03 g/mol = 1.47 mol
1168 kJ /4 mol NH₃ x 1.47 mol NH₃ = 429.4 kJ
CH₄ + 2O₂ ---> CO₂ + 2H₂O
16g..................................18g×2
16g CH₄ --- 36g H₂O
5,1g CH₄ --- X
X = (5,1×36)/16
X = 11,475g H₂O
Answer:
[MgCl₂] = 0.036 M
Explanation:
Molarity are the moles of solute in 1L of solution.
For this case, our solution's volume is 2L
First of all, we convert the mass of solute (MgCl₂) to moles
6.92 g . 1mol / 95.2 g = 0.0727 moles
Now, we make a rule of three:
In 2L of solution we have 0.0727 moles of solute
Then, in 1L of solution we may have, 1L . 0.0727 mol / 2L = 0.036 M
