Answer:
Explanation:
Combustion reaction is given below,
C₂H₅OH(l) + 3O₂(g) ⇒ 2CO₂(g) + 3H₂O(g)
Provided that such a combustion has a normal enthalpy,
ΔH°rxn = -1270 kJ/mol
That would be 1 mol reacting to release of ethanol,
⇒ -1270 kJ of heat
Now,
0.383 Ethanol mol responds to release or unlock,
(c) Determine the final temperature of the air in the room after the combustion.
Given that :
specific heat c = 1.005 J/(g. °C)
m = 5.56 ×10⁴ g
Using the relation:
q = mcΔT
- 486.34 = 5.56 ×10⁴ × 1.005 × ΔT
ΔT= (486.34 × 1000 )/5.56×10⁴ × 1.005
ΔT= 836.88 °C
ΔT= T₂ - T₁
T₂ = ΔT + T₁
T₂ = 836.88 °C + 21.7°C
T₂ = 858.58 °C
Therefore, the final temperature of the air in the room after combustion is 858.58 °C
Answer:
they're losing electrolytes
Explanation:
When athletes sweat, they're losing electrolytes primarily in the form of sodium (Na+) and chloride (Cl-), so when you start to replace lost fluids, ahtletes should replace the electrolytes as well. Potassium (K+), Magnesium (Mg2+) and Calcium (Ca2+) are electrolytes also lost through sweating.
Answer:it will sink in water
Explanation:
Periodic table<span> of the </span>elements, in chemistry, the organized<span> array of all the chemical </span>elements<span> in order of increasing atomic number—i.e., the total number of protons in the atomic nucleus.</span>
Answer:
2350kg of Al₂O₃
Explanation:
<u><em>Step 1 : Write the balanced chemical equation:</em></u>
4Al + 3O₂ → 2Al₂O₃
<u><em>Step 2: Find the Ratio of Al :</em></u> Al₂O₃
Al : Al₂O₃
4 : 2
2 : 1
4700: 2350
= 2350kg of Al₂O₃
