Question

1. A sample of aluminum absorbs 50.1 J of heat, upon which the temperature of the sample increases from 20.0°C to 35.5°C. If the specific heat of aluminum is 0.900 J/g- °C, what is the mass, in grams, of the sample?

Answer 1

Answer:

Mass of aluminium in sample = 3.591 g ≅ 3.6 grams

Explanation:

Given that,  A sample of aluminum absorbs 50.1 J of heat, upon which the temperature of the sample increases from 20.0°C to 35.5°C.

the specific heat of aluminum is 0.900 J/g- °C

The relation between heat absorbed and change in temperature is given by,   Q = msΔT.

where Q = heat absorbed

            m = mass of the substance

            s = specific heat of substance

          ΔT  = change in temperature

Now, in our case, Q = 50.1 J ; s = 0.900 J/g- °C; ΔT= 35.5-20 = 15.5°C

⇒ m =  $\frac{Q}{s(T_{2} -T_{1}) }$

⇒ m = $\frac{50.1}{0.900(15.5)}$ = 3.591 g ≅ 3.6 g

⇒ m ≅ 3.6 g