The layers of the atmosphere are defined by variations in temperature and pressure with altitude. These include the troposphere (0 to 16 km), stratosphere (16 to 50 km), mesosphere (50 to 80km) and thermosphere (80 to 640km).
Answer:
Characteristics of noble gases :
- Conduct electricity.
- Odorless.
- Colorless.
Hope it helps!
Answer:
C. When there are more particles in the same space, they collide
more often.
Explanation:
<span>_____Balanced Chemical eqn___
C6H5OH + 7O2 --> 6C02 + 3H20
Firstly, heat of rxn will be absorbed by bobm calorimaeter, so find the qcal
qcal = CΔT
= (11.66 KJ/°C)(26.37°C- 21.36°C)
= 58.42 KJ
since the heat of rxn absorbed by calorimeter, assume:
qrnx = -qcal
= - 58.42 KJ
_____q GRAM OF C6H5OH______
Find the number of moles you have by dividing the given grams of C6H5OH by its molar mass
(1.8 g C6H5OH)(94 g/mole C6H5OH) = 0.0191 mol C6H5OH
then divide qrnx by the number of moles.
(-58.42 KJ)/(0.0191 mol C6H5OH) = -3058.64 KJ/mol C6H50H</span>
Answer
is: the final pressure of the gas is closest to 3,17 atm.
<span><span>
p</span>₁ =
3,2 atm.</span><span>
T₁ =
310 K.</span><span>
V₁ =
6 L.</span><span>
p₂ = ?</span><span>
T₂ =
410K.</span><span>
V₂ = 8,0 L.</span><span>
<span>Use combined gas law - the volume of amount of gas is proportional to the ratio of
its Kelvin temperature and its pressure.</span><span>
p</span></span><span>₁V₁/T₁ =
p₂V₂/T₂.</span><span>
<span>3,2 atm · 6,0 L ÷ 310 K = p</span>₂ · 8,0 L ÷ 410 K.</span><span>
0,0619 = 0,0195p</span><span>₂.</span><span>
p</span><span>₂ =
3,17 atm.</span>
