Answer:
4050 mL
Explanation:
Given data:
Mass of glucose = 150.1 g
Molarity of solution = 0.205 M
Volume of solution = ?
Solution:
Molarity = number of moles of solute / L of solution.
Now we will calculate the moles of sugar first.
Number of moles = mass/ molar mass
Number of moles = 150.1 g/ 180.156 g/mol
Number of moles = 0.83 mol
Now we will determine the volume:
Molarity = number of moles of solute / L of solution.
0.205 M = 0.83 mol / L of solution.
L of solution = 0.83 mol / 0.205 M
L of solution = 4.05 L
L to mL conversion:
4.05 L × 1000 mL / 1 L = 4050 mL
Answer:
Nitrate is considered SOLUBLE
Explanation:
please kindly refer to attachment for the step by step solution of the given problem.
Answer:
Preserving natural resources such as farmland, parks, open spaces and unused land is one way to reduce urban sprawl. Preserving the land keeps it as is. Thus, wildlife and animals aren't removed from their homes and forced closer to cities and suburbs
Answer:
+523 kJ.
Explanation:
The following data will be used to calculate the average C-S bond energy in CS2(l).
S(s) ---> S(g)
ΔH = 223 kJ/mol
C(s) ---> C(g)
ΔH = 715 kJ/mol
Enthalpy of formation of CS2(l)
ΔH = 88 kJ/mol
CS2(l) ---> CS2(g)
ΔH = 27 kJ/mol
CS2(g) --> C(g) + 2S(g)
So we must construct it stepwise.
1: C(s) ---> C(g) ΔH = 715 kJ
2: 2S(s) ---> 2S(g) ΔH = 446 kJ
adding 1 + 2 = 3
ΔH = 715 + 446
= 1161 kJ
3: C(s) + 2S(s) --> C(g) + 2S(g) ΔH = 1161 kJ
4: C(s) + 2S(s) --> CS2(l) ΔH = 88 kJ
adding (reversed 3) from 4 = 5
ΔH = -1161 + 88
= -1073 kJ
5: C(g) + 2S(g) --> CS2(l) ΔH = -1073 kJ
6: CS2(l) ---> CS2(g) ΔH = 27 kJ
adding 5 + 6 = 7
ΔH = -1073 + 27
= -1046 kJ
7. C(g) + 2S(g) --> CS2(g) ΔH = -1046 kJ
Reverse and divide by 2 for C-S bond enthalpy
= -(-1046)/2
= +523 kJ.
