Answer:
Volume is 1.065L
Explanation:
Hello,
We can easily solve this problem by using general gas equation.
PV / T = K
P1V1/T1 = P2V2/T2
Data;
P1 = 3.0atm
P2 = 1.0atm
T1 = 20°C = (20 + 273.15)K = 293.15K
T2 = 20°C = (20 + 273.15)K = 293.15K
V1 = 355mL = 0.355L
V2 = ?
From the data given, we can substitute it into the equation,
(P1 × V1) / T1 = (P2 × V2) / T2
(3.0 × 0.355) / 293.15 = (1.0 × V2) / 293.15
1.065 = 1.0V2
Divide both sides by 1.0
V2 = 1.065L
The volume of CO₂ released is 1.065L
The answer for that kind of question depends on many things. location, how many people will inhabit the home, whether or not the home is a vacation home or a full time home. etc. P.S. I do not believe that this has anything to do with chemistry
Answer:
[H₃O⁺] = 3.162 × 10⁻⁹ moles / liter
Explanation:
The pH is calculated with the formula:
pH = -lg[H₃O⁺]
From here the concentration of hydronium ion (H₃O⁺) will be:
[H₃O⁺] =
[H₃O⁺] =
[H₃O⁺] = 3.162 × 10⁻⁹ moles / liter
Answer:
K2CO3 = K2O + CO2
Explanation:
In a chemical equation, the number of atoms on the left needs to be balanced with the number of atoms on the right, and there has to be the same number of the same *type* of atom on both sides as well.
On the left:
2 K
1 C
3 O
and on the right,
2 K
1 O
On the right, there are a few atoms missing, specifically, 1 C and 2 O.
The missing atoms then should be added to the side missing the atoms, preferably in a stable molecule. Luckily, CO2 contains exactly 1 C, and 2 O s, and is quite stable. So, a "CO2" has to be added on the left
Answer:
a. 0.171M
b. 0.0938M
c. 0.284
d. 1.99atm
e. 1.88
Explanation:
Hello,
In this case, for the given reaction whose balance should be corrected as:
For which the law of mass action, in terms of the change due to stoichiometry and the reaction extent, turns out:
Thus, the initial concentration of hydrogen sulfide is:
Now, since the equilibrium amount of sulfur is given, the change due to equilibrium reaching is:
Therefore:
a. Equilibrium concentration of hydrogen:
b. Equilibrium concentration of hydrogen sulfide:
c.) Equilibrium constant, Kc:
d.) Partial pressure of sulfur gas:
e. Kc, for the reaction:
In that case, it equals the inverse halved initial reaction, whose modification is related as:
Best regards.