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Morgarella [4.7K]
2 years ago
12

16. These conditions occur over the course of a day. Cumulus clouds appear and create rain showers. The sky clears soon after th

e showers. The temperature drops after the sky clears. Which weather event is most likely moving through the area?
A. tornado

b. hurricane

c.cold front

d. warm front​
Chemistry
1 answer:
olya-2409 [2.1K]2 years ago
6 0

Answer:

A

Explanation:

I believe it's A gggggg%gggggtggg

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I think that beryllium is formed in alcohol I think
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Amino acids can be synthesized by reductive amination. Draw the structure of the organic compound that you would use to synthesi
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Answer:

Following are the answer to this question:

Explanation:

For the reductive amination of its carbonyl group, amino acids could be synthesized by reducing ammunition, which can be synthesized in the given attachment file:

please find the attachment:

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3 years ago
Cuántos gramos de hidróxido de sodio (NaOH) se debe de agregar a un litro de agua para obtener una disolución al 25% en masa
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Answer:

= 250 gramos

Explanation:

No ha preguntado sobre peso / peso o peso / volumen.

Para w / v:

Simplemente tome el 25% de 1000 y luego agréguelo en 1L de agua

La masa de NaOH necesaria es de 250 g.

Para w / w:

250 gramos de NaOH y 750 g de agua, hará que la solución sea 1L.

5 0
2 years ago
How many grams of sodium acetate ( molar mass = 83.06 g/mol ) must be added to 1.00 Liter of a 0.200 M acetic acid solution to m
Pie

<u>Answer:</u> The mass of sodium acetate that must be added is 30.23 grams

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of acetic acid solution = 0.200 M

Volume of solution = 1 L

Putting values in above equation, we get:

0.200M=\frac{\text{Moles of acetic acid}}{1L}\\\\\text{Moles of acetic acid}=(0.200mol/L\times 1L)=0.200mol

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a+\log(\frac{[\text{salt}]}{[\text{acid}]})  

pH=pK_a+\log(\frac{[CH_3COONa]}{[CH_3COOH]})

We are given:

pK_a = negative logarithm of acid dissociation constant of acetic acid = 4.74

[CH_3COONa]=?mol  

[CH_3COOH]=0.200mol

pH = 5.00

Putting values in above equation, we get:

5=4.74+\log(\frac{[CH_3COONa]}{0.200})

[CH_3COONa]=0.364mol

To calculate the mass of sodium acetate for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of sodium acetate = 83.06 g/mol

Moles of sodium acetate = 0.364 moles

Putting values in above equation, we get:

0.364mol=\frac{\text{Mass of sodium acetate}}{83.06g/mol}\\\\\text{Mass of sodium acetate}=(0.364mol\times 83.06g/mol)=30.23g

Hence, the mass of sodium acetate that must be added is 30.23 grams

7 0
3 years ago
What are the two variables that affect the electric force between two objects?
givi [52]

Explanation:

The electrical force between two objects is given by the formula as follows :

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So, the two force between two charged objects depends on the product of charges and distance between charges.

5 0
2 years ago
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