Answer: Current in a wire
We can use the same right-hand rule as we did for the moving charges—pointer finger in the direction the current is flowing, middle finger in the direction of the magnetic field, and thumb in the direction the wire is pushed.
Explanation:
2.36 x 10^-1
You move the decimal to right behind the first significant digit and the exponent on the 10 is how many places you moved that decimal. You can type it into a calculator to check it as well if you're not sure.
Answer:

Explanation:
It is given that,
Mass of bundle of shingles, m = 10 kg
Upward acceleration of the shingles, 
The radius of the motor of the pulley, r = 0.17 m
Let T is the tension acting on the shingles when it is lifted up. It can be calculated as :



T = 113 N
Let
is the minimum torque that the motor must be able to provide. It is given by :



So, the minimum value of torque is 19.21 N-m. Hence, this is the required solution.
Answer:
D. TA < TB
Explanation:
From general gas equation, we know that:
PV = nRT
PV/R = nT
where,
P = pressure of gas
V = volume of gas
R = General gas constant
T = temperature of gas
n = no. of moles of gas
<u>FOR CYLINDER A</u>:
PV/R = (nA)(TA) _____ eqn (1)
<u>FOR CYLINDER B</u>:
PV/R = (nB)(TB) _____ eqn (2)
Because, Pressure, Volume are constant for both cylinders.
Comparing eqn (1) and (2)
(nA)(TA) = (nB)(TB)
It is given that the amount of gas in cylinder A is twice as much as the gas in cylinder B. This means the number moles in cylinder A are twice as much as no. of moles in cylinder B.
nA = 2(nB)
using this in eqn:
2(nB)(TA) = (nB)(TB)
TA = (1/2)(TB)
<u>TA = 0.5 TB</u>
Therefore it is clear that the correct option is:
<u>D. TA<TB</u>
Answer:
a) v = 88.54 m/s
b) vf = 26.4 m/s
Explanation:
Given that;
m = 1400.0 kg
a)
by using the energy conservation
loss in potential energy is equal to gain in kinetic energy
mg × ( 3200-2800) = 1/2 ×m×v²
so
1400 × 9.8 × 400 = 0.5 × 1400 × v²
5488000 = 700v²
v² = 5488000 / 700
v² = 7840
v = √7840
v = 88.54 m/s
b)
Work done by all forces is equal to change in KE
W_gravity + W_non - conservative = 1/2×m×(vf² - vi²)
we substitute
1400 × 9.8 × ( 3200-2800) - (5 × 10⁶) = 1/2 × 1400 × (vf² -0 )
488000 = 700 vf²
vf² = 488000 / 700
vf² = 697.1428
vf = √697.1428
vf = 26.4 m/s