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PolarNik [594]
3 years ago
10

An nfl linebacker can go from 0 m/s to 2.5 m/s in 2.5s. What is his acceleration?

Physics
1 answer:
dybincka [34]3 years ago
5 0

Answer:

a= 1 m/s^2

Explanation:

a= (Vf-Vi)/t

a=(2.5m/s - 0m/s)/2.5 s

a=2.5 m/s / 2.5 s

a= 1 m/s^2

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Jose is batting for the home team when he hits a foul ball that rises straight up over home plate. A fan in the stands notices t
andreyandreev [35.5K]

Answer:

<h3><em>28.01m/s.</em></h3>

Explanation:

Given maximum height reached by the ball as H = 40 metres

Since the ball rises straight up when hit by a ball, then the angle of launch will be perpendicular to the ground and that is 90°.

To determine the upward speed of the ball in meters per second after it got struck by the bat, we will use the formula for calculating the maximum height according to projectile motion;

Maximum Height H = \frac{u^2sin^2\theta}{2g} where;

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Substituting the given parameters into the formula;

40 = \frac{u^2sin^2(90)}{2(9.81)}\\ \\40 = \frac{u^2}{2(9.81)}\\ \\40 = \frac{u^2}{19.62} \\cross\ multiply\\\\u^2 = 40*19.62\\u^2 = 784.8\\u = \sqrt{784.8}\\ u = 28.01 m/s

<em>Hence the upward speed of the ball in meters per second after it got struck by the bat is 28.01m/s.</em>

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