Answer:
1.) 1620 km/h^2
2.) 2.7 km
Explanation:
1.) Given that the car start from rest. The initial velocity U will be equal to zero. That is,
U = 0.
Final velocity V = 54 km/h
Time t = 2 minute = 2/60 = 1/30 hour
Acceleration a will be change in velocity per time taken. That is,
a = ( V - U )/ t
Substitute V, U and t into the formula
a = 54 ÷ 1/30
a = 54 × 30 = 1620 km/h ^2
2.) Distance travelled S by the car during the time can be calculated by using the 2nd equation of motion.
S = Ut + 1/2at^2
Substitute all the parameters into the formula
S = 54 × 1/30 + 1/2 × 1620 × (1/30)^2
S = 54/30 + 810 × 1/900
S = 54/30 + 810/900
S = (1620+810)/900
S = 2430/900
S = 2.7 km.
Therefore, distance travelled by the car during this time is 2.7 km
Energy flows with kinetic energy
Answer:
25N
Explanation:
formula=> Frictional force= coefficient of friction x normal reaction
normal reaction is mass x gravity(10N/kg)
so Frictional force= 0.5x5x10
=25N
but that is the Frictional force not the constant force
to get the constant force, subtract the Frictional force from the weight of the block
weight= mass x gravity
= 5x10
= 50N
50N-25N
=25N
Explanation:
Given that,
Radius of divalent cation, 
Radius of monovalent anion, 
Charge for divalent cation, 
Charge for monovalent cation, 
The sum of radii of both cations and anion is, 
(a) The force of attraction between two ions is given by :
(b) Let F' is the force of repulsion at this same distance such that,
F + F' = 0
So, 
Hence, this is the required solution.
