Answer:
I don't know but you got this!!
The question is incomplete, the complete question is;
The compound magnesium phosphate has the chemical formula Mg3(PO4)2. In this compound, phosphorus and oxygen act together as one charged particle, which is connected to magnesium, the other charged particle. What does the 2 mean in the formula 5Mg3(PO4)2? A. There are two elements in magnesium phosphate. B. There are two molecules of magnesium phosphate. C. There are two magnesium ions in a molecule of magnesium phosphate. D. There are two phosphate ions in a molecule of magnesium phosphate.
Answer:
There are two phosphate ions in a molecule of magnesium phosphate.
Explanation:
The compound magnesium phosphate is an ionic compound. Ionic compounds always consists of two ions, a positive ion and a negative ion.
In this case, the positive ion is Mg^2+ while the negative ion is PO4^3-.
The subscript, 2 after the formula of the phosphate ion means that there are two phosphate ions in each formula unit of magnesium phosphate.
<u>Hello and Good Morning/Afternoon</u>:
<em>Original Question: C₂H₅OH + __O₂ → __CO₂ + __ H₂O</em>
<u>To balance this equation</u>:
⇒ must ensure that there is an equal number of elements on both sides of the equation at all times
<u>Let's start balancing:</u>
- On the left side of the equation, there are 2 carbon molecule
⇒ but only so far one on the right side
C<em>₂H₅OH + __O₂ → 2CO₂ + __ H₂O</em>
- On the left side of the equation, there are 6 hydrogen molecules
⇒ but only so far two on the right side
C<em>₂H₅OH + __O₂ → 2CO₂ + 3H₂O</em>
- On the right side of the equation, there are 7 oxygen molecules
⇒ but only so far three on the left side
C<em>₂H₅OH + 3O₂ → 2CO₂ + 3H₂O</em>
<u>Let's check and make sure we got the answer:</u>
C<em>₂H₅OH + 3O₂ → 2CO₂ + 3H₂O</em>
<em> 2 Carbon ⇔ 2 Carbon</em>
<em> 6 Hydrogen ⇔ 6 Hydrogen</em>
<em> 7 Oxygen ⇔ 7 oxygen</em>
<u>Thefore the coefficients in order are</u>:
⇒ 1, 3, 2, 3
<u>Answer: 1,3,2,3</u>
Hope that helps!
#LearnwithBrainly<em> </em>
Answer:
The velocity of the skateboard is 0.774 m/s.
Explanation:
Given that,
The spring constant of the spring, k = 3086 N/m
The spring is stretched 18 cm or 0.18 m
Mass of the student, m = 100 kg
Potential energy of the spring, 
To find,
The velocity of the car.
Solution,
It is a case of conservation of energy. The total energy of the system remains conserved. So,






v = 0.774 m/s
So, the velocity of the skateboard is 0.774 m/s.