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1 year ago

The magnetic lines of force always travel from north to south true or false

Physics

1 answer:

kumpel [21]1 year ago

7 0

Answer:

True

Explanation:

Magnetic field lines outside of a permanent magnet always run from the north magnetic pole to the south magnetic pole. Therefore, the magnetic field lines of the earth run from the southern geographic hemisphere towards the northern geographic hemisphere.

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If an object of mass m1 = 0.55 ???????? is sliding without friction in the +x-direction on a level surface at a speed of ????1 =

tatiyna

Answer:

$ME = 0.14 J$

$P = 0.396 kg m/s$

Explanation:

As we know that for perfectly elastic collision total mechanical energy is always conserved

so we will have

$ME = \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2$

$ME = \frac{1}{2}0.55(0.72^2) + \frac{1}{2}0.55(0^2)$

$ME = 0.14 J$

now we also know that total moment of the system is conserved in any collision because there is no external force on it

so we will have

$P = m_1v_1 + m_2v_2$

$P = 0.55(0.72) + 0$

$P = 0.396 kg m/s$

6 0

3 years ago

An air track car with a mass of 6 kg and velocity of 4 m/s to the right collides with a 3 kg car moving to the left with a veloc

sammy [17]

Remember that moment before collision is equal to the moment after collision.

$(m1 \times u1) + (m2 \times u2) = (m1 \times v1) + (m2 \times u2)$

Plugging in our values,

$(6 \times 4) - (3 \times 2) = (6 \times 1) + (3 \times v2) \\ 24 - 6 = 6 \times 3v2 \\ 18 = 18v2 \\ v2 = 1 {ms}^{ - 1}$

8 0

2 years ago

the average power of the Sun is 3.79x1026 Watts, answer the following questions: 13. What is the average intensity of light at E

Lemur [1.5K]

Explanation:

Given that,

Average power of sun $P=3.79\times10^{26}\ Watt$

We need to calculate the intensity of light at Earth's position

Using formula of intensity

$I=\dfrac{P_{avg}}{4\pi r^2}$

Where, I = intensity

P = power

Put the value into the formula

$I=\dfrac{3.79\times10^{26}}{4\pi\times(1.496\times10^{11})^2}$

$I=1347.616\ W/m^2$

So, The intensity is 1347.616 W/m².

(A). We need to calculate the pressure on a solar sail due to the light of the sun if it's fully reflective

Using formula for fully reflective

$P = \dfrac{2I}{c}$

Put the value into the formula

$P=\dfrac{2\times1347.616}{3\times10^{8}}$

$P=8.984\times10^{-6}\ N/m$

(B). We need to calculate the pressure on a solar sail due to the light of the sun if it's fully reflective

Using formula for fully absorptive

$P=\dfrac{I}{c}$

$P=\dfrac{1347.616}{3\times10^{8}}$

$P=4.492\times10^{-6}\ N/m$

Hence, This is the required solution.

6 0

2 years ago

A football player kicks a ball horizontally off a hill with an initial velocity of 42.0 m/s. It travels a horizontal distance of

damaskus [11]

Explanation:

.........................

7 0

3 years ago

A lemon with mass 0.3 kg falls out of a tree from a height of 1.8 m. How much mechanical energy does the lemon have just before

Zina [86]

Mechanical energy is the energy that is possessed by an object due to its motion or due to its position. It can either be kinetics or potential. In this problem you know it starting position so you can calculate it's potential energy (PE):

<span>PE=mass∗gravity∗height=0.3kg∗9.8m/s2∗1.8m=?

</span>The answer will typically be given in joules:

1J=kg∗m2s2 Could be wrong... But I believe it is 5.3...? as a final product.

3 0

3 years ago

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