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mr_godi [17]
3 years ago
14

I need help on this plz

Mathematics
1 answer:
notsponge [240]3 years ago
3 0
A & B satisfy the equation
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PLEASE HELP !!!!!<br> What is the value of the missing angle?
vazorg [7]

Answer:

B

Step-by-step explanation:

180 - 100 = 80

80 = 30 = 110

180 - 110 = 70

6 0
3 years ago
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Can someone please help me with this question
aniked [119]
2/9 divided by 1/2.   invert the second fraction and multiply

2/9  *  2/1 = 4/9
6 0
4 years ago
Compare and contrast the rate 4/5 mile in 8 minutes and 4 minutes to travel 2/5 mile
Gwar [14]

The values of the rates 4/5 mile in 8 minutes and 4 minutes to travel 2/5 mile are equal

<h3>How to compare and contrast the rates?</h3>

The rates are given as:

Rate 1 = 4/5 mile in 8 minutes

Rate 2 = 2/5 mile in 4 minutes

Calculate the above rates

This is done as follows:

Rate 1 = 1/10 mile per minute

Rate 2 =1/10 mile per minute

When the rates are calculated, the values are 1/10 mile per minute

Hence, the values of the rates 4/5 mile in 8 minutes and 4 minutes to travel 2/5 mile are equal

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5 0
2 years ago
Draw clearly the graph of the linear equation. y=1/2x, where x= (-4 -2, 0, 2, 4)​
aniked [119]

Answer:

(in attachment)

Step-by-step explanation:

you can find the points by inputting the x-values into the equation to solve for the y-values, then connecting the plotted points to create the line.

When x=-4

y=1/2(-4)

y=-2

(-4,-2)

Repeat for all values.

6 0
3 years ago
Hakim deposited $50 in a saving account earning 10% interest, compounded annually . To the nearest cent , how much interest will
Paraphin [41]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$50\\ r=rate\to 10\%\to \frac{10}{100}\dotfill &0.10\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}

\bf A=50\left(1+\frac{0.10}{1}\right)^{1\cdot 2}\implies A=50(1.1)^2\implies A=60.5 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{earned interest}}{60.5 - 50\implies 10.5}~\hfill

7 0
3 years ago
Read 2 more answers
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