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mars1129 [50]
3 years ago
10

How much heat is required to change temperature of 2g of water from 34°C to 68°C? (Water has a specific heat of 4.18)

Chemistry
1 answer:
statuscvo [17]3 years ago
4 0

Answer: B

Explanation:

To find the amount of heat required, you would use q=mcΔT.

q=2g(4.18J/g°C)(68-34°C)

q=284.2 J

*Please ignore the capital A in the equation. I can't find a way to type in the degree sign into the equation without the A appearing.

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The density of water is 1.00 g/ml at 4°c. how many water molecules are present in 2.56 ml of water at this temperature?
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Answer:

             8.55 × 10²² Molecules

Solution:

Step 1: Calculate the Mass of Water as;

                       Density  =  Mass ÷ Volume

Solving for Mass,

                       Mass  =  Density × Volume

Putting values,

                       Mass  =  1 g.mL⁻¹ × 2.56 mL

                       Mass  =  2.56 g

Step 2: Calculate Moles of Water as,

                       Moles  =  Mass ÷ M.Mass

Putting values,

                       Moles  =  2.56 g ÷ 18 g.mol⁻¹

                       Moles  =  0.142 mol

Step 3: Calculate Number of Molecules of Water as,

                       # of Molecules  =  Moles × 6.022 × 10²³

Putting value of mole,

                       # of Molecules  =  0.142 × 6.022 × 10²³

                       # of Molecules  =  8.55 × 10²² Molecules

5 0
3 years ago
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