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4 years ago

This is the fundamental force which holds particles together to form protons and neutrons

2 answers:

8 0

The four fundamental forces of nature are gravity, electromagnetism, the weak force, and the strong force.
The strong force is what holds particles together to form protons and neutrons.

Zinaida [17]4 years ago

3 0

The correct answer is a strong force

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Which of the following would most likely be an example of a mass-transit disaster?

Aleonysh [2.5K]

Answer:

i think it is c if not im sorry if im wrong

Explanation:

7 0

3 years ago

A cannon is mounted on a tower above a wide, level field. The barrel of the cannon is 20 m above the ground below. A cannonball

OLga [1]

<u>Answer:</u>

Cannonball will be in flight before it hits the ground for 2.02 seconds

<u>Explanation:</u>

Initial height from ground = 20 meter.

We have equation of motion , $s= ut+\frac{1}{2} at^2$ , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

In this the velocity of body in vertical direction = 0 m/s, acceleration = 9.8 $m/s^2$ , we need to calculate time when s = 20 meter.

Substituting

$20=0*t+\frac{1}{2} *9.8*t^2\\ \\ t = 2.02 seconds$

So it will take 2.02 seconds to reach ground.

5 0

3 years ago

The series circuit shown below, what would happen if one of the light bulbs and its attached wire segment were removed?

rewona [7]

Answer:

The remaining lights would shine with the same brightness.

Explanation:

6 0

3 years ago

A proton orbits a long charged wire, making 1.80 ×106 revolutions per second. The radius of the orbit is 1.20 cm What is the wir

Fantom [35]

Answer:

linear charge density = -9.495 × $10^{-34}$ C/m

Explanation:

given data

revolutions per second = 1.80 × $10^{6}$

radius = 1.20 cm

solution

we know that when proton to revolve around charge wire then centripetal force is require to be in orbit of radius around provide by electric force

- q × E = m × w² × r ..................1

- 9 × $10^{9}$ × $\frac{2*linear\ charge\ density}r}$ q = m × w² × r ............2

and w = $\frac{2*\pi}{T}$

w = $\frac{d\theta }{dt}$

w = 1.80 × $10^{6}$ × $\frac{2*\pi}{1}$

w = 11304000 rad/s

so here from equation 2

- 9 × $10^{9}$ × $\frac{2*linear\ charge\ density}{0.012}$ 1.80 × $10^{6}$ = 1.672 × $10^{-27}$ × 11304000² × 0.0120

linear charge density = -9.495 × $10^{-34}$ C/m

8 0

3 years ago

A student drops a ball off the top of building and records that the ball takes 3.82s to reach the ground. Determine all unknowns

klemol [59]

Explanation:

Given parameters:

Time of drop = 3.82s

Unknown:

Final velocity of the ball = ?

Height of fall = ?

Solution:

To solve this problem, we apply the appropriate motion equation.

To find the final velocity;

v = u + gt

v is the unknown final velocity

u is the initial velocity = 0m/s

g is the acceleration due to gravity = 9.8m/s²

t is the time

v = 0 + 9.8 x 3.82 = 37.4m/s

Height of drop;

H = ut + $\frac{1}{2}$ gt²

So;

H = (0 x 3.82) + ( $\frac{1}{2}$ x 9.8 x 3.82²) = 71.5m

4 0

3 years ago