Answer:
force on the proton = 5.96 × 
N
Explanation:
given data
kinetic energy = 1.16 ×
eV
charge density of σ = +6.60 μC/m²
solution
we get here force on the proton that is express as
F = qE ....................1
here q is charge on proton i.e = 1.6 × 
C
and E is electric field due to charge i.e E = 
so put the value in equation 1 we get
force on the proton = 1.6 × × 
force on the proton = 5.96 × N
Answer:
7m
Explanation:
5+2=7 and then I added in the "m" and got 7m, so presumably g=7m.
The strength of the electric field at that point and the force would this charge experiences at that point will be 4.587 N/C and 12.38 N.
<h3>
</h3><h3>What is the electric field strength?</h3>
The electric field strength is defined as the ratio of electric force to charge.
Given data;
q₁ = 5.4 C
F₁ is the electric force in case1
E is the electric field =?
F₂ is the electric force in case 2
q₂ is the charge 2
The strength of the electric field at that point is;
F₁=Eq₁
E₁=F/q₁
E₁=25.0 N / 5.4 C
E₁=4.587 N/C
The force would this charge experience at that point when the charge is 2.7 C;
F₂=Eq₂
F₂=4.587 N/C × 2.7 C
F₂ = 12.38 N
Hence the strength of the electric field at that point and the force would this charge experiences at that point will be 4.587 N/C and 12.38 N.
To learn more about the electric field strength, refer to the link;
brainly.com/question/4264413
#SPJ1
degree celcius and degreee frahanit
Answer:
Velocity is the rate at which the position changes. The average velocity is the displacement or position change (a vector quantity) per time ratio.
Hope this helps! ^-^
