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viktelen [127]
2 years ago
9

If the elephant were then allowed to fall straight down, how fast would it be moving when it landed back on the ground?

Physics
1 answer:
Oxana [17]2 years ago
6 0

Answer:

0 mph because it is probably dead

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Steel blocks A and B, which have equal masses, are at TA = 300 oC and T8 = 400 oC. Block C, with mc - 2mA, is at TC = 350 oC. Bl
shepuryov [24]

Answer:

b) TA = TB = TC

Explanation:

  • When put in contact each other, and isolated, both blocks will exchange heat till they reach to thermal equilibrium.
  • During this process, the body at a higher temperature, will loss heat, tat it will be gained by the other body.
  • The equilibrium condition will be reached when the following equation be met:

       \Delta Q = c_{st}* m_{A} * (T_{fin}  - T_{0A} ) = c_{st}* m_{B} * (T_{0B}  - T_{fin} )

  • Replacing by the values of T₀A = 300º C, and T₀B = 400ºC, and simplifying common terms as mA = mB, we can solve for  Tfin, as follows:

       (400 \ºC - T_{fin}) = (T_{fin} - 300 \ºC) \\ \\  2* T_{fin} = 700\ºC\\ \\ T_{fin} = 350\ºC

  • So, when both blocks reach to equilibrium, they will be at a common final temperature, 350ºC.
  • When put in contact with block C, at the same temperature, at that instant, the three blocks will have the same common temperature of 350 ºC.
  • So, option b) is the right one.
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