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miskamm [114]
3 years ago
12

oleg ran 8.8 miles in 1 hour 20 minutes. assuming he continues at a constant rate, how long will it take him to run any number o

f miles
Mathematics
2 answers:
Usimov [2.4K]3 years ago
8 0
V = d/t = 8.8 miles/[80/60] hours = 6.6 miles/hour

t = d/v = d/6.6

Answer: d/6.6, where d is the number of miles to run.
Arisa [49]3 years ago
5 0

Answer:

(6.62 × d) hours.

Step-by-step explanation:

Oleg ran in 1 hour 20 minutes = 8.8 miles

1 hour 20 minutes = 1.33 hours

Formula of speed = \frac{Distance}{time}

His average speed of running = \frac{8.8}{1.33}

                                                  = 6.616 ≈ 6.62 miles/hour

Let the distance to run = d miles

it take him to run = (6.62 × d)

It will take (6.62 × d) hours to run.

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Find the midpoint of PQ with endpoints P (-4, 3) and Q (4,-1) . Then write an equation of the line that passes through the midpo
Marianna [84]

Answer:

Equation of the line  that passes through the midpoint and is perpendicular to PQ is   2 x - y +1 = 0

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given points are P( -4 ,3 ) and Q ( 4,-1)

Mid -point of PQ

                     =      (\frac{x_{1} + x_{2} }{2} , \frac{y_{1} + y_{2} }{2} )

                    =       (\frac{-4+4}{2} , \frac{3-1}{2} ) = ( 0 , 1 )

<u> Step(ii):</u>-

Slope of PQ

             m = \frac{y_{2}-y_{1}  }{x_{2} -x_{1} } = \frac{-1-3}{4+4} = \frac{-4}{8} = \frac{-1}{2}

The slope of the line is Perpendicular to PQ

           m_{2} = \frac{-1}{m_{1} } = \frac{-1}{\frac{-1}{2} } = 2

Equation of the line  that passes through the midpoint and is perpendicular to PQ

      y - y_{1}  = m ( x - x_{1} )

          y - 1  = 2 ( x - 0 )

         2 x - y +1 = 0

<u>Final answer:-</u>

Equation of the line  that passes through the midpoint and is perpendicular to PQ

 2 x - y +1 = 0

           

           

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Answer:

0.0958

Step-by-step explanation:

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