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miskamm [114]
3 years ago
12

oleg ran 8.8 miles in 1 hour 20 minutes. assuming he continues at a constant rate, how long will it take him to run any number o

f miles
Mathematics
2 answers:
Usimov [2.4K]3 years ago
8 0
V = d/t = 8.8 miles/[80/60] hours = 6.6 miles/hour

t = d/v = d/6.6

Answer: d/6.6, where d is the number of miles to run.
Arisa [49]3 years ago
5 0

Answer:

(6.62 × d) hours.

Step-by-step explanation:

Oleg ran in 1 hour 20 minutes = 8.8 miles

1 hour 20 minutes = 1.33 hours

Formula of speed = \frac{Distance}{time}

His average speed of running = \frac{8.8}{1.33}

                                                  = 6.616 ≈ 6.62 miles/hour

Let the distance to run = d miles

it take him to run = (6.62 × d)

It will take (6.62 × d) hours to run.

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6:10

Step-by-step explanation:

To solve this problem, find the time 2 hours and 14 minutes before 8:24.

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5 0
2 years ago
A student walk 60m on a bearing
Katena32 [7]

Answer:

d = 234.6 m

Step-by-step explanation:

You can consider a system of coordinates with its origin at the beginning of the walk of the student.

When she start to walk, she is at (0,0)m. After her first walk, her coordinates are calculated by using the information about the incline and the distance that she traveled:

x_1=60cos28\°=52.97m\\\\y_1=60sin28\°=28.16m

she is at the coordinates (52.97 , 28.16)m.

Next, when she walks 180m to the east, her coordinates are:

(52.97+180 , 28.16)m = (232.97 , 28.16)m

To calculate the distance from the final point of the student to the starting point you use the Pythagoras generalization for the distance between two points:

d=\sqrt{(x-x_o)^2+(y-y_o)^2}\\\\x=232.97\\\\x_o=0\\\\y=28.16\\\\y_o=0\\\\d=\sqrt{(232.97-0)^2+(28.16-0)^2}m=234.6m

The displacement of the student on her complete trajectory was of 234.6m

8 0
3 years ago
Can i please get the answer to this?
Artist 52 [7]
4x+10=90
4x=80
x=20
Why 90°? This is because the angle subtended in a semi-circle to the circumference is 90°.
6 0
3 years ago
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