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miskamm [114]
3 years ago
12

oleg ran 8.8 miles in 1 hour 20 minutes. assuming he continues at a constant rate, how long will it take him to run any number o

f miles
Mathematics
2 answers:
Usimov [2.4K]3 years ago
8 0
V = d/t = 8.8 miles/[80/60] hours = 6.6 miles/hour

t = d/v = d/6.6

Answer: d/6.6, where d is the number of miles to run.
Arisa [49]3 years ago
5 0

Answer:

(6.62 × d) hours.

Step-by-step explanation:

Oleg ran in 1 hour 20 minutes = 8.8 miles

1 hour 20 minutes = 1.33 hours

Formula of speed = \frac{Distance}{time}

His average speed of running = \frac{8.8}{1.33}

                                                  = 6.616 ≈ 6.62 miles/hour

Let the distance to run = d miles

it take him to run = (6.62 × d)

It will take (6.62 × d) hours to run.

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stephanie read 72 pages on sunday and 83 pages on Monday. About how many pages did Stephanie read during the two days ?
frutty [35]
155 pages because if you add 72and83 you will get 155 because 2 plus3 is 5 and 7 plus 8 is fiveteen
4 0
3 years ago
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(2^x+y , 3^x-y )= (16,9) find the value of x and y
Jet001 [13]

Answer:

x=3,y=1

Step-by-step explanation:

2^x+y=16,3^x-y=9

16=2^4,9=3^2

x+y=4,x-y=2 add both

2x=6,x=3

3-y=2,y=1

7 0
2 years ago
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The corporate team building event will cost $12 if it has three attendees if there are five attendees how much was a quaker team
Norma-Jean [14]

Answer:

Cost to arrange the event for 5 attendees will be $20.

Step-by-step explanation:

We have to solve this question by calculating the unit rates or unitary method.

Since cost to arrange corporate team building event for 3 attendees is = $12

Cost to arrange the event for 1 attendee will be = \frac{12}{3} = $4

Therefore, cost to arrange the event for five attendees will be = 5×4 = $20

4 0
3 years ago
show that the points (1 ,7) ,(4, 2), (-1, -1) and (-4, 4) taken in order are the vertics of a square. Also find its area
OLga [1]

Answer:

Step-by-step explanation:

A (1 ,7) ,   B(4, 2),  C(-1, -1) and D(-4, 4)

Find the distance of sides using distance formula.

Distance = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

A (1 ,7) ,   B(4, 2)

AB = \sqrt{(4-1)^{2}+(2-7)^{2}}\\\\    =\sqrt{3^{2}+(-5)^{2}}\\\\  \\   = \sqrt{9+25}=\sqrt{34} units\\\\\\\\BC = \sqrt{(-1-4)^{2}+(-1-2)^{2}}\\\\ =\sqrt{(-5)^{2}+(-3)^{2}}     = \sqrt{25+9}=\sqrt{34} units\\\\\\CD = \sqrt{(-4-[-1])^{2}+(4-[-1])^{2}}\\\\=\sqrt{(-4+1)^{2}+(4+1)^{2}}\\\\=\sqrt{(-3)^{2}+(5)^{2}}\\\\=\sqrt{9+25} =  \sqrt{34} units\\\\\\AD = \sqrt{(-4-1)^{2}+(4-7)^{2}}\\\\=\sqrt{(-5)^{2}+(-3)^{2}}  =\sqrt{25+9} =  \sqrt{34} units

AB = BC = CD = AD = √34 units. so , ABCD is  a square.

Area of square = side * side

                          = √34 * √34

                          = 34 square units

7 0
3 years ago
Graph the equations y=x-2 and x + y = 6 on the grid provided.
Colt1911 [192]

Formulas:

y=x-2

y=-1x+6

You'll basically just graph these which you said you can do, and if you don't want to, just input these formulas in Desmos Graphing Calculator, and the point that they intersect is your answer for the point of intersection

7 0
2 years ago
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