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3 years ago

Why might kinneys Decrease urine production in someone who is sweating a lot on a hot day?

Chemistry

1 answer:

Oduvanchick [21]3 years ago

3 0

Answer:

During exercise and heat stress, both glomerular filtration and renal blood flow are markedly reduced, resulting in decreased urine output. Therefore, when fluids are over consumed during exercise (hyperhydration), there may be a reduced ability to produce urine to excrete the excess volume

Explanation: On an average temperature day, your body will usually produce about 1 to 2 quarts of urine. Cold weather will result in your body needing to filter more blood than normal as blood is rushing to your vital organs at a higher frequency. This results in you having to pee more often.

It is concluded profuse sweating exercise results in a decrease of urinary uric acid excretion amounts and leads to increased serum uric acid after the exercise

this is some information i have to help you

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Which one of the following substances would be the most soluble in CCl4?

maria [59]

Answer: Option (d) is the correct answer.

Explanation:

Carbon tetrachloride $(CCl_{4})$ is a non-polar solvent. Whereas out of the given options, $Na_{2}SO_{4}$ , $H_{2}O$ , $CH_{3}CH_{2}CH_{2}CH_{2}OH$ , and HI are all polar molecules.

On the other hand, only $C_{4}H_{10}$ is non-polar molecule.

Also it is known that like dissolves like.

So, being non-polar $CCl_{4}$ will dissolve the give alkane, $C_{4}H_{10}$ .

5 0

3 years ago

You have 28.5 g of iron shot that has a volume of 3.60 mL. From this information, calculate the density of iron.

laila [671]

Answer:

$\boxed {\boxed {\sf \rho \approx 7.917 \ g/mL}}$

Explanation

Density can be found by dividing the mass by the volume.

$\rho=\frac{m}{v}$

We know the iron sheet has a mass of 28.5 grams and the volume is 3.60 milliliters.

$m= 28.5 \ g \\d= 3.60 \ mL$

Substitute the values into the formula.

$\rho=\frac{28.5 \ g}{ 3.60 \ mL}$

Divide.

$\rho = 7.91666667 \ g/mL$

Let's round to the nearest thousandth.

The 6 in the ten-thousandth tells us to round the 6 to a 7.

$\rho \approx 7.917 \ g/mL$

The density of iron is about <u>7.917 grams per milliliter.</u>

8 0

2 years ago

Your teacher created a 2 g/L salt-water solution (solution A) and a 2.5 g/L salt-water solution (solution B), both in 500 mL of

Genrish500 [490]

solution B is concentrated

Explanation:

3 0

3 years ago

What is the composition, in atom percent, of an alloy that consists of a) 5.5 wt% Pb and b) 94.5 wt% of Sn? Assume that the atom

Anastaziya [24]

Answer : The percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

Explanation :

First we have to calculate the number of atoms in 5.5 wt% Pb and 94.5 wt% of Sn.

As, 207.2 g of lead contains $6.022\times 10^{23}$ atoms

So, 5.5 g of lead contains $\frac{5.5}{207.2}\times 6.022\times 10^{23}=1.59\times 10^{22}$ atoms

and,

As, 118.71 g of lead contains $6.022\times 10^{23}$ atoms

So, 94.5 g of lead contains $\frac{94.5}{118.71}\times 6.022\times 10^{23}=4.79\times 10^{23}$ atoms

Now we have to calculate the percent composition of Pb and Sn in atom.

$\% \text{Composition of Pb}=\frac{\text{Atoms of Pb}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100$

$\% \text{Composition of Pb}=\frac{1.59\times 10^{22}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=3.21\%$

and,

$\% \text{Composition of Sn}=\frac{\text{Atoms of Sn}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100$

$\% \text{Composition of Sn}=\frac{4.79\times 10^{23}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=96.8\%$

Thus, the percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

6 0

3 years ago

Find the volume of 20g of H₂ at STP<br><br>

ANEK [815]

Answer:224

Explanation:

We should answer it with Stoichiometry

We say: 20 g H2× (1 mol/ 2g)× ( 22.4 lit/ 1 mol) = 224

Means: we have 20 grams and every 2g H2, equals to 1 mol of it and every 1 mol of H2, equals to 22.4 lit( because of STP)

hope you got this:)

6 0

3 years ago