All categories

3 years ago

Why might kinneys Decrease urine production in someone who is sweating a lot on a hot day?

Chemistry

1 answer:

Oduvanchick [21]3 years ago

3 0

Answer:

During exercise and heat stress, both glomerular filtration and renal blood flow are markedly reduced, resulting in decreased urine output. Therefore, when fluids are over consumed during exercise (hyperhydration), there may be a reduced ability to produce urine to excrete the excess volume

Explanation: On an average temperature day, your body will usually produce about 1 to 2 quarts of urine. Cold weather will result in your body needing to filter more blood than normal as blood is rushing to your vital organs at a higher frequency. This results in you having to pee more often.

It is concluded profuse sweating exercise results in a decrease of urinary uric acid excretion amounts and leads to increased serum uric acid after the exercise

this is some information i have to help you

You might be interested in

Explain why the quantum number set (3, 2, 3, -½) is not possible for an electron in an atom

Triss [41]

Ok the ML (the 3rd number) is not legit because the ML value can only be from -L to L (the second value)

7 0

3 years ago

How many atoms are in 5.5 moles of carbon dioxide

Veronika [31]

Answer: I think the answer is, 3.312177825e+24 atoms

Explanation: I had a problem similar to this, Hope this helps!

4 0

3 years ago

Read 2 more answers

Which subatomic particle is electrically neutral and found in the nucleus of an atom

Alexxx [7]

Neutron. Its is foumd inside nucleus along with protons and are electrically neutral.

7 0

3 years ago

Will a precipitate form (yes or no) when 50.0 ml of 1.2 × 10–3 m pb(no3)2 are added to 50.0 ml of 2.0 × 10–4 m na2s? if so, iden

frez [133]

Answer:

Yes, a precipitate of PbS forms

Explanation:

The equation of the reaction is given as:

Pb(NO₃)₂ + Na₂S → PbS + 2NaNO₃

The lead sulfide forms a precipitate in the aqeous solution.

Precipitation is a form of reaction in which ions combines to form a solid precipiate. Most double displacement reactions in which ionic compounds are the reactants results in formation of a precipitate as the product.

There are rules of solubility which guides a reaction that would lead to the formation of a precipitate. The mos applicable of the rules to the reaction stated above is that "carbonates, phosphates, sulfides, oxides and hydroxides are insolube". The sulfide of lead formed in the product is therefore insoluble.

8 0

3 years ago

Complete and balance the following redox reaction in acidic solution As2O3(s) + NO3- (aq) → H3AsO4(aq) + N2O3(aq)

scoray [572]

Answer:

$As_{2}O_{3}(s)+2NO_{3}^{-}(aq)+2H_{2}O(l)+2H^{+}(aq)\rightarrow 2H_{3}AsO_{4}(aq)+N_{2}O_{3}(aq)$

Explanation:

Oxidation: $As_{2}O_{3}(s)\rightarrow H_{3}AsO_{4}(aq)$

Balance As: $As_{2}O_{3}(s)\rightarrow 2H_{3}AsO_{4}(aq)$
Balance H and O in acidic medium: $As_{2}O_{3}(s)+5H_{2}O(l)\rightarrow 2H_{3}AsO_{4}(aq)+4H^{+}(aq)$
Balnce charge: $As_{2}O_{3}(s)+5H_{2}O(l)-4e^{-}\rightarrow 2H_{3}AsO_{4}(aq)+4H^{+}(aq)$ ......(1)

Reduction: $NO_{3}^{-}(aq)\rightarrow N_{2}O_{3}(aq)$

Balance N: $2NO_{3}^{-}(aq)\rightarrow N_{2}O_{3}(aq)$
Balance H and O in acidic medium: $2NO_{3}^{-}(aq)+6H^{+}(aq)\rightarrow N_{2}O_{3}(aq)+3H_{2}O(l)$
Balance charge: $2NO_{3}^{-}(aq)+6H^{+}(aq)+4e^{-}\rightarrow N_{2}O_{3}(aq)+3H_{2}O(l)$ ......(2)

$Equation (1)+Equation (2)$ gives-

$As_{2}O_{3}(s)+2NO_{3}^{-}(aq)+2H_{2}O(l)+2H^{+}(aq)\rightarrow 2H_{3}AsO_{4}(aq)+N_{2}O_{3}(aq)$

3 0

3 years ago

Read 2 more answers