Answer:
orbital speed of the electrons in their orbit will increase
Explanation:
As we know that centripetal force for electrons will be due to electrostatic attraction force of electron.
So it is given as
so we have
now on the left side if the force of attraction will increase and hence there must be the change in that part of equation
So here at the same position the speed of the electron
So we can say that correct answer will be
orbital speed of the electrons in their orbit will increase
Answer:
a) A = 0.603 m , b) a = 165.8 m / s² , c) F = 331.7 N
Explanation:
For this exercise we use the law of conservation of energy
Starting point before touching the spring
Em₀ = K = ½ m v²
End Point with fully compressed spring
=
= ½ k x²
Emo =
½ m v² = ½ k x²
x = √(m / k) v
x = √ (2.00 / 550) 10.0
x = 0.603 m
This is the maximum compression corresponding to the range of motion
A = 0.603 m
b) Let's write Newton's second law at the point of maximum compression
F = m a
k x = ma
a = k / m x
a = 550 / 2.00 0.603
a = 165.8 m / s²
With direction to the right (positive)
c) The value of the elastic force, let's calculate
F = k x
F = 550 0.603
F = 331.65 N
Answer:
Explanation:
If there is a dielectric slab with thickness less than the distance between the plates is inserted inside a capacitor, then that capacitor can be regarded as two capacitors connected in series.
Let's assume that the slab is placed onto the lower side. So, the capacitance of that part of the capacitor, C1 is
where is the permittivity of the slab.
The other part of the capacitor is
Two capacitors are connected in series:
If we know the charge of the plates, we could relate the potential V0 to capacitance via