Hi there,
In a molecule<span>, </span>atoms<span> are bonded together by single, double, or triple bonds. An </span>atom<span> has a nucleus surrounded by electrons. ... So another </span>difference between atoms and molecules<span> is that when similar </span>atoms<span> combine together in varying numbers,</span>molecules<span> of different properties can be formed.
hope you understand</span>
Answer: The ground-state electronic configuration of
1) ![Ru^{2+}=[Kr]4d^6](https://tex.z-dn.net/?f=Ru%5E%7B2%2B%7D%3D%5BKr%5D4d%5E6)
2) ![W^{3+]=4f^{14}5d^3](https://tex.z-dn.net/?f=W%5E%7B3%2B%5D%3D4f%5E%7B14%7D5d%5E3)
Explanation: The electronic configuration of elements is defined as the distribution of electrons around the nucleus of that element. It depends on the atomic number of the element.
Atomic number of the element = Number of electrons.
Atomic number = 44
Number of electrons = 44
Electronic configuration of Ru-element = ![[Kr]4d^75s^1](https://tex.z-dn.net/?f=%5BKr%5D4d%5E75s%5E1)
To form
, 2 electrons are released from the neutral Ru-element.
So, the electronic configuration of ![Ru^{2+}=[Kr]4d^6](https://tex.z-dn.net/?f=Ru%5E%7B2%2B%7D%3D%5BKr%5D4d%5E6)
Atomic number = 74
Number of electrons = 74
Electronic configuration of W-element = ![[Xe]4f^{14}5d^46s^2](https://tex.z-dn.net/?f=%5BXe%5D4f%5E%7B14%7D5d%5E46s%5E2)
To form
, 3 electrons are released from the neutral W-element.
So, the electronic configuration of ![W^{3+}=[Xe]4f^{14}5d^3](https://tex.z-dn.net/?f=W%5E%7B3%2B%7D%3D%5BXe%5D4f%5E%7B14%7D5d%5E3)
Answer: Phosphorus 3143.58=1.4 1
Oxygen 1656.42=3.5 2.5
Explanation:
Answer:
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