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yan [13]
3 years ago
5

The width of a rectangular prism is five less than the length, and the height of the prism is twice the length. Let x

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
3 0
The answer is c xs 8.5 units trust me
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(PICTURE ATTACHED) please help
lisabon 2012 [21]

Answer:

D

Step-by-step explanation:

0.000009 = 9×10^-6

0.00000003 = 3×10^-8

9×10^-6 / 3×10^-8 =

9/3 × 10^(-6+8) = 3 × 10^2

5 0
4 years ago
A coat regularly cost $125 is put on sale for $75
Stels [109]
If a coat is regularly $125, and they mark it down to $75, we could figure out how much money was taken off by subtracting $75, from $125

$125 - $75 = $50

So the coats price was cut by $50.

Hope it helps
Please mark brainliest!
7 0
3 years ago
The triangle shown below has an area of 16 units squared
pashok25 [27]
The area of the triangle is 16 un squared
6 0
3 years ago
How do I find the y intercept in a fraction
Furkat [3]

ANSWER:

Both functions have the same slope

The linear equation does not have a y-intercept

The table and the grahp express an equivalent function

STEP-BY-STEP EXPLANATION:

In order to compare, we must calculate the slope of the table, knowing that the equation in its slope and intercept form is the following:

\begin{gathered} y=mx+b \\ \text{where m is the slope and b is y-intercept} \end{gathered}

The formula to calculate the slope is the following:

m=\frac{y_2-y_1}{x_2-x_1}

The points are (-6, -9/2) and (4,3), replacing:

m=\frac{3-(-\frac{9}{2})}{4-(-6)}=\frac{3+\frac{9}{2}}{4+6}=\frac{\frac{15}{2}}{10}=\frac{15}{20}=\frac{3}{4}

The slope is 3/4

Now, for b

x = 4

y = 3

m = 3/4

replacing:

\begin{gathered} 3=\frac{3}{4}\cdot4+b \\ b=3-3 \\ b=0 \end{gathered}

The equation is:

y=\frac{3}{4}x

Therefore, the true statements are:

• Both functions have the same slope

,

• The linear equation does not have a y-intercept

,

• The table and the grahp express an equivalent function

8 0
1 year ago
F(x) = -4x + 9 and g(x) = 2x - 7,<br> find f ( g (x))
o-na [289]
F=5 if I’m not mistaking
5 0
3 years ago
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