Answer:
Step-by-step explanation:
common difference is 6
Let's solve your equation step-by-step.
2(x+4)=−5x+1
Step 1: Simplify both sides of the equation.
2(x+4)=−5x+1
(2)(x)+(2)(4)=−5x+1(Distribute)
2x+8=−5x+1
Step 2: Add 5x to both sides.
2x+8+5x=−5x+1+5x
7x+8=1
Step 3: Subtract 8 from both sides.
7x+8−8=1−8
7x=−7
Step 4: Divide both sides by 7.
7x
7
=
−7
7
x=−1
Answer:
x=−1
The parent function of the function represented in the table is <u>exponential</u>.
- Note if you subtract 10 from each output, you get
.
If function f was translated down 4 units, the <u>f(x)</u> values would be <u>decreased by 4</u>.
A point on the table for the transformed function would be <u>(4, 87).</u>
Answer:
p = 1
Step-by-step explanation:
Given
3p - 6 + 7 = 32 - 4(2p + 5), that is
3p + 1 = 32 - 4(2p + 5) ← distribute and simplify right side
3p + 1 = 32 - 8p - 20
3p + 1 = 12 - 8p ( add 8p to both sides )
11p + 1 = 12 ( subtract 1 from both sides )
11p = 11 ( divide both sides by 11 )
p = 1
keeping in mind that 4 months is not even a year, since there are 12 months in a year, 4 months is then 4/12 years.
let's assume is simple interest.
![\bf ~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$34300\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ t=years\to \frac{4}{12}\dotfill &\frac{1}{3} \end{cases} \\\\\\ A=34300\left[ 1+(0.035)\left( \frac{1}{3} \right) \right]\implies A= 34300(1.011\overline{6})\implies A=34700.1\overline{6}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%20%5Ctextit%7BSimple%20Interest%20Earned%20Amount%7D%20%5C%5C%5C%5C%20A%3DP%281%2Brt%29%5Cqquad%20%5Cbegin%7Bcases%7D%20A%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%20P%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cdotfill%20%26%20%5C%2434300%5C%5C%20r%3Drate%5Cto%203.5%5C%25%5Cto%20%5Cfrac%7B3.5%7D%7B100%7D%5Cdotfill%20%260.035%5C%5C%20t%3Dyears%5Cto%20%5Cfrac%7B4%7D%7B12%7D%5Cdotfill%20%26%5Cfrac%7B1%7D%7B3%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20A%3D34300%5Cleft%5B%201%2B%280.035%29%5Cleft%28%20%5Cfrac%7B1%7D%7B3%7D%20%5Cright%29%20%5Cright%5D%5Cimplies%20A%3D%2034300%281.011%5Coverline%7B6%7D%29%5Cimplies%20A%3D34700.1%5Coverline%7B6%7D)