by angular momentum conservation we will have
angular momentum of child + angular momentum of merry go round = 0
angular momentum of child = mvR
m = mass of child
R = radius of child
v = speed = 2 m/s
now let's say moment of inertia of merry go round is I
so we will have
so merry go round will turn in opposite direction with above speed
Answer:
The right sphere is negatively charged, the left sphere is charged positively.
Explanation:
When a negatively charged rod is held above the top of left sphere, the rod will attract positive charges and repel negative charges. As the sphere are initially touching each other so positive charges from the both spheres will moves toward the rod. When we separate the spheres positive charges from right sphere have already moved toward the rod i.e. left sphere, creating a deficiency of positive charges in the right sphere and excessiveness of positive charges in left sphere , hence the right sphere will remain negatively charged and left sphere will remain positively charged.
Answer:
10.19 m
Explanation:
Water will rise to equalize the pressure inside and outside the tube.
The equation of pressure is given by
Where,
p = Pressure of air = 10⁵ N/m²
ρ = Density of water = 10³ kg/m³
g = Acceleration due to gravity = 9.81 m/s²
h = Height the water will rise
∴ The water will rise by 10.19 m.