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Basile [38]
3 years ago
5

An object with charge q=−6.00×10−9C is placed in a region of uniform electric field and is released from rest at point A. After

the charge has moved to point B, 0.500 m to the right, it has kinetic energy 3.00×10−7J.
(a) If the electric potential at point A is +30.0 V, what is the electric potential at point B?
(b) What are the magnitude and direction of the electric field?
Physics
1 answer:
shtirl [24]3 years ago
8 0

Answer:

its a

Explanation:

used google

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2 kg

Explanation:

Acceleration = 5 m/s^2

Force = 10 N

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mass = force / acceleration

mass = 10 / 5

mass = 2 kg

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taurus [48]

Answer:

31,360J

Explanation:

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That implies, gpe = mgh

Therefore substituting the values of m and h as given in the question, knowing in mine that the acceleration due to gravity( g) is 9.8 N/kg, will give 31,360J

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6 0
3 years ago
A plastic box has an initial volume of 2.00 m 3 . It is then submerged below the surface of a liquid and its volume decreases to
nikitadnepr [17]

Answer:

Volume strain is 0.02

Explanation:

Volume strain is defined as the change in volume to the original volume.

It is given that,

Initial volume of the plastic box is 2 m³

It is then submerged below the surface of a liquid and its volume decreases to 1.96 m³

We need to find the volume strain on the box. It is defined as the change in volume divided by the original volume. So,

\delta V=\dfrac{V_f-V_i}{V_i}\\\\\delta V=\dfrac{1.96-2}{2}\\\\\delta V=0.02

So, the volume strain on the box is 0.02.

6 0
3 years ago
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