The acceleration of the wagon along the ground is 3.6 m/s².
To solve the problem above, we need to use the formula of acceleration as related to force and mass.
Acceleration: This can be defined as the rate of change of velocity.
⇒ Formula:
- Fcos∅ = ma................. Equation 1
⇒ Where:
- F = Force
- ∅ = angle above the horizontal
- m = mass of the wagon
- a = acceleration of the wagon
⇒ make a the subject of equation 1
- a = Fcos∅/m..................... Equation 2
From the question,
⇒ Given:
⇒ Substitute these values into equation 2
- a = 44(cos35°)/10
- a = 44(0.8191)/10
- a = 3.6 m/s²
Hence, The acceleration of the wagon along the ground is 3.6 m/s²
Learn more about acceleration here: brainly.com/question/9408577
Answer:
55.80s
Explanation:
Power is calculated using the expression
Power = Work done/Time
Workdone= Force ×distance
Workdone = 794×22
Work done = 17468Joules
From the power formula
Time = Workdone/Power
Time = 17468/313
Time = 55.80seconds
The elevator takes 55.80seconds to life the Taylor
Answer:
3rd class lever
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