6/6+ 12*180
= 1+ 2,160
= 2,161
The final answer is 2,161~
To find the rate, you must divide the distance traveled by the time it took.
17.5 m is the distance while time it took was 5 seconds.
So,
17.5 ÷ 5 = 3.5 m/s
The rate of the anchor is 3.5 m/s
Note: I did not ignore the negative sign in the distance but rather acknowledged it as a magnitude. This meant that the anchor was dropping down instead of going up.
Y= kx+b, k-slope, b-intercept
so
2=k*1+b
7=k*2+b
12=k*3+b
17=k*4+b
solve these two equation:
2=k*1+b
7=k*2+b
second minus first is 7-2=2k-k+b-b
5=k,
so we know k=5
put this in any equation 2=5*1+b
b=2-5
b=-3
check this in
12=5*3-3 - right
17=5*4-3 - right
Answer: y=5x-3
