Answer:
The answer to this equation would be -19
Hope this helps!
We have:
The generic equation of the line is: y-yo = m (x-xo)
The slope is:
m = (y2-y1) / (x2-x1)
m = (- 2-0) / (3-0)
m = -2 / 3
We choose an ordered pair
(xo, yo) = (0, 0)
Substituting values:
y-0 = (- 2/3) (x-0)
Rewriting:
y = (- 2/3) x
Answer:
The equation of the line is:
y = (- 2/3) x
Answer:
hope you understand the answers
Okie dokie,
When converting a decimal, you use the place the decimal is in...
Let's review the places: tenths, hundredths, thousandths, etc.
You look at the last number to determine what place you're using!
-------------------
Now here's an example for the
tenths place:
.5
it's in the tenths place, right? so put it over that number (with no decimal) over a
10.
(mobile) 5/10 or

Now, decide if you can simplify. You can! 5/10 simplifies down to
1/2.

is your answer!
--------
Example for the
hundredths place:
.26
the last number is in the hundredths place, so put the number (without a decimal) over
100!26/100 or

You can simplify this!
13/50 is your answer!
Calculators can also come in handy!
Good luck!
Answer:

We can find the second moment given by:

And we can calculate the variance with this formula:
![Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246](https://tex.z-dn.net/?f=%20Var%28X%29%20%3DE%28X%5E2%29%20-%5BE%28X%29%5D%5E2%20%3D%207.496%20-%282.5%29%5E2%20%3D%201.246)
And the deviation is:

Step-by-step explanation:
For this case we have the following probability distribution given:
X 0 1 2 3 4 5
P(X) 0.031 0.156 0.313 0.313 0.156 0.031
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.
The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).
We can verify that:

And 
So then we have a probability distribution
We can calculate the expected value with the following formula:

We can find the second moment given by:

And we can calculate the variance with this formula:
![Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246](https://tex.z-dn.net/?f=%20Var%28X%29%20%3DE%28X%5E2%29%20-%5BE%28X%29%5D%5E2%20%3D%207.496%20-%282.5%29%5E2%20%3D%201.246)
And the deviation is:
