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butalik [34]
3 years ago
13

The diatomic molecule of chlorine, cl2, is held together by a(n)____ covalent bond.

Chemistry
1 answer:
kvasek [131]3 years ago
7 0

Answer : The diatomic molecule of chlorine, Cl₂, is held together by a SINGLE covalent bond.

Covalent Bond :

It is type of chemical bond, which is formed by sharing of electron between atoms . The covalent bond is formed between two non metals . The valance electron are shared to form the bond . The shared electrons are known as BONDING electron pair and the electron pair which do not take part in bonding are known as NON- BONDING electron pair. Example : O₂ , H₂ , H₂O, NH₃ etc .

Formation of covalent bond in Cl₂ :

Chlorine is present in group 17 in p block , It is a non metal .

The electronic configuration of Cl is : 1s² 2s² 2p⁶ 3s² 3p⁵ .

Since the outer shell is n= 3 , which has 7 electrons in it , hence Cl has 7 valence electrons in it .

From electronic configuration , it can be seen that Cl need 1 electron to complete its octet (3s² 3p⁶ ). Hence when two Cl atoms come close they share one-one electron with each other (as shown in image ) .

Now the octet of both the atom are complete and they are in stable state together .

When both Cl atom share one e⁻ , there is a bond formed between Cl atoms . One bond consists of 2⁻ . Hence in Cl₂ SINGLE covalent bond present .

Cl + Cl -> Cl₂

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The property of a substance stays ______________ no matter how the substance is used.
Irina18 [472]

Any substance changes to another substance that means the change of the physical property. Like water () has different state which changes as the temperature changes. It remain as liquid in the room temperature, in solid form at or below 0°C and vapor phase on or above 100°C. But in all the stage or phase of the substance the composition of the water i.e.  remains. Thus the chemical property remains fixed when a substance change to other substance.  

3 0
3 years ago
Arrange the following ions in order of increasing ionic radius.
Zepler [3.9K]

Answer:

Ca 2+ <K  +  <Ar<Cl  −  <S  2−

Explanation:

Ar,K  + ,Cl  − ,S  2− ,Ca  2+

 have the same number of electrons. Their radii would be different because of their different nuclear charges. The cation with the greater positive charge will have a smaller radius because of the greater attraction of the electrons to the nucleus. Anion with the greater negative charge will have the larger radius. In this case, the net repulsion of the electrons will outweigh the nuclear charge and the ion will expand in size. Hence the correct order will be Ca  

2+  <K +  <Ar<Cl  −  <S  2−

 

3 0
2 years ago
Construct <br> an isotope has 17 protons 20 neutrons and 18 electrons
ASHA 777 [7]
Add proton + neutrons = Mass 37

Proton is same as your atomic mass= 17

If you go on the periodic table look up 17 and it will give u the letter.
4 0
3 years ago
A spectrophotometer measures the transmittance or the absorbance, or both, of a particular wavelength of light after it has pass
Cerrena [4.2K]

Answer:Answer: The step that is NOT necessary to complete before a cuvette is placed into the spectrophotometer is option B (Write, in ink, either sample or blank on the side of the cuvette to keep track of them)

Explanation: spectrophotometer is an instrument used to measure the light intensity absorbed after being passed through a solution. Before the absorbance of the sample solution, a solvent solution called blank is used for the calibration of the machine and this blank solvent is placed in a cuvette. The procedure usually comes first before the main sample is processed. Therefore there is no need to

Write, in ink, either sample or blank on the side of the cuvette to keep track of them. This is so since sample and blank is not absorbed at the same time by the machine.

7 0
3 years ago
Read 2 more answers
Please help this test ends in 30 min
RideAnS [48]

Answer:

Option C

CH₃CH₂CH₂COOH

Explanation:

Carbonxylic acids are compounds which has the general formula

R–COOH where R is an alkyl group.

Considering the options given in the question above,

For A:

CH₃CH₂OCH₂CH₃ is an ether compound with general formula ROR' where R and R' are both alkyl group.

For B:

CH₃CH₂CH₂CH₂OH is an alcohol with general formula ROH where R is an alkyl group.

For C:

CH₃CH₂CH₂COOH is a carbonxylic acid with general formula R–COOH where R is an alkyl group.

For D:

CH₃CH₂C=OCH₂CH₃ is a ketone compound with general formula RC=OR' where R and R' are both alkyl group

For E:

ClCH₂CH₂CH₂CH₂CH₂CH₂Br is simply an Alkyl halide with general formula XRX where X is an halogen (i.e F, Cl, Br or I) and R is an alkyl group.

From the above illustration, only option C contains a Carbonxylic compound.

8 0
3 years ago
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