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4 years ago

Give three examples of liquid substances in which you would expect dipole-dipole attractions to be large.

1 answer:

6 0

Polar molecules HCl, CHCl3, CH3F is the answer. There is a difference between the electronegativity of the atoms. E.G. the F atom and the C in CH3F

This creates partial charges on them, which are responsible for dipole-dipole forces.

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How can farming affect the ecosystem?

Bezzdna [24]

The Correct Answer Is/ Runoff often carries pesticides from farmers' fields that can damage aquatic ecosystems.

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4 years ago

The reaction of 2-methylbutane with chlorine would yield how many monochloro derivatives (include stereoisomers)?

zimovet [89]

The reaction of 2 methylbutane with chlorine yield 5 monochloro derivative. Methylbutane has four carbon atoms which react with chlorine. The carbon with antibonding will be chiral and it will react with chlorine. there will be four difference group around chiral carbon hence it will have stereoisomers.

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3 years ago

Read 2 more answers

The reference point in motion is:

lyudmila [28]

Answer: the focal point

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3 years ago

What is the relationship between molar mass in grams per mole (g/mol) and average atomic mass in amu of each element?

navik [9.2K]

Answer:

The molar mass and atomic mass are essentially the same for an element

Explanation:

The molar mass of a substance can be obtained by dividing the mass of the substance by the no of moles of the substance present.

The atomic mass of an element is the number of protons and neutrons present in the substance.

These two measurements usually give the same values because they both make reference to the 1/12th the mass of carbon-12 for their measurement.

Because they both have the same reference point, though they have different calculating procedures, the results obtained will be similar.

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4 years ago

German physicist Werner Heisenberg related the uncertainty of an object\'s position (Δx) to the uncertainty in its velocity Δv.

Assoli18 [71]

Heisenberg's Uncertainty Principle gives a relationship between the standard deviation of an object's position and its momentum.

$\Delta p \cdot \Delta x = h / (4 \pi)$ where

$\Delta p$ the standard deviation of the object's momentum,
$\Delta x$ the standard deviation of the object's position, and
$h \approx 6.63 \times 10^{-34} \; \text{J} \cdot \text{s}$ the Planck's constant.

By definition, the momentum of the electron equals the product of its mass and velocity.

$p = m\cdot v$

Assuming that measurement of the mass of the electron $m$ is accurate. It is assumed to be a coefficient of constant value. The standard deviation in the electron's velocity is thus directly related to that of its mass. That is:

$\Delta p = m \cdot \Delta v$

$\Delta v = 0.01 \times 10^{6} \;\text{m}\cdot \text{s}^{-1}$ from the question;

$\Delta p = m\cdot v \\ \phantom{\Delta p} = 0.01 \times 10^{6} \; \text{m} \cdot \text{s}^{-1} \times 9.11 \times 10^{-31} \; \text{kg}\\\phantom{\Delta p} = 9.11 \times 10^{-27} \; \text{kg} \cdot \text{m}\cdot \text{s}^{-1}$

Convert the unit of the Planck's constant to base SI units (kg, m, s, etc.) if it was provided in derived units such as joules. Doing so would allow for a dimension analysis on the accuracy of the result.

$h = 6.63 \times 10^{-34} \; \text{J} \cdot \text{s}\\\phantom{h} = 6.63 \times 10^{-34} \; (\text{N}\cdot \text{m}) \cdot \text{s} \\\phantom{h} = 6.63 \times 10^{-34} \; ((\text{kg} \cdot \text{m}\cdot \text{s}^{-2}) \cdot \text{m}) \cdot \text{s}\\\phantom{h} = 6.63 \times 10^{-34} \; \text{kg} \cdot \text{m}^{2} \cdot \text{s}^{-1}$

Apply the Uncertainty Principle:

$\Delta x = h/ (4 \pi \cdot \Delta p)\\\phantom{\Delta x} = 6.63 \times 10^{-34} \; \text{kg} \cdot \text{m}^{2} \cdot \text{s}^{-1} / (4 \pi \cdot 9.11\times 10^{-27} \; \text{kg} \cdot \text{m}\cdot \text{s}^{-1})\\\phantom{\Delta x} = 5.79 \times 10^{-9} \; \text{m}$ .

Dimensional analysis:

$\Delta x$ resembles the standard deviation of a position measurement. It is expected to have a unit of meter, which is the same as that of position.

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3 years ago