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Bas_tet [7]
3 years ago
11

To determine the pressure in a fluid at a given depth with the air-filled cartesian diver, we can employ Boyle's law, which stat

es that the pressure in an ideal gas (held at constant temperature) is inversely proportional to its volume. At a fluid's surface, the pressure of the fluid is the same as the pressure of the atmosphere just above it, which we'll denote as LaTeX: P_{atm}P a t m. If the volume of air, which can be treated as an ideal gas here, in the cartesian diver decreases by 19% as it is lowered to a specific depth in the fluid, the pressure of the fluid at this depth, in terms of atmospheric pressure, is
Physics
1 answer:
aniked [119]3 years ago
6 0

Answer:

The pressure at this depth is 1.235\cdot P_{atm}.

Explanation:

According to the statement, the uncompressed fluid stands at atmospheric pressure. By Boyle's Law we have the following expression:

\frac{P_{2}}{P_{1}} = \frac{V_{1}}{V_{2}} (1)

Where:

V_{1}, V_{2} - Initial and final volume.

P_{1}, P_{2} - Initial and final pressure.

If we know that V_{2} = 0.81\cdot V_{1}, then the pressure ratio is:

\frac{P_{2}}{P_{1}} = 1.235

If P_{1} = P_{atm}, then the final pressure of the gas is:

P_{2} = 1.235\cdot P_{atm}

The pressure at this depth is 1.235\cdot P_{atm}.

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3 years ago
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