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The mass of MgO needed to produce 4.8 tonnes of Mg is
8 tonnes or 2,000 Kg or 2,000 ,000 g
calculation
Si + 2 MgO = SiO2 +2 Mg
step 1 :find the moles of Mg
moles = mass/molar mass
mass = 4.8 tonnes = 480,000 g
molar mass = 24 g/mol
moles is therefore = 480,000 g/24g/mol = 200,000 moles
then by use of mole ratio between MgO to Mg which is 1:1 therefore the moles of MgO is also = 200,000 moles
mass of MgO = moles of MgO x molar mass of MgO
molar mass of MgO = 24 + 16 =40 g/mol
therefore the mass = 200,000 moles x 40 g/mol = 8,000,000 grams or 8,000,000/1000= 8,000 Kg or 8,000/1000 = 8 tonnes
<u>Answer: </u>The equation which is wrong is
<u>Explanation:</u>
For the given reaction:
The expression for is given by:
The concentration of solids are taken to be 1, only concentration of gases and liquid states are taken. The pressure of only gases are taken.
Relationship between is given by the expression:
where,
= number of moles of gaseous products - number of moles of gaseous reactants
R = gas constant
T= temperature
For the above reaction,
= number of moles of gaseous products - number of moles of gaseous reactants = 0 - 3 = -3
Hence, the expression for is:
Therefore, the equation which is wrong is