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lidiya [134]
3 years ago
8

Whats two answers I know B is wrong

Chemistry
2 answers:
Goshia [24]3 years ago
7 0

Answer:

C and D

Explanation:

IF CORRECT PLEASE GIVE ME BRAINLLEST!!!!!!!!!!

IF NOT PLEASE TELL ME, AND IF YOU KNOW, WHY!!!!!!

<em>THANKS!!!!!!!!!!!</em>

<em>◑﹏◐:-)O_o(○’ω’○)∩﹏∩↖(^ω^)↗o_O(ToT)^O^囧rzB-)</em>

JulijaS [17]3 years ago
6 0

Answer:A and D

Explanation:

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What mass of KNO3 would be needed to produce 18.4 liters of oxygen gas, measured at 1.50 x 10^3 kPa and 15 degrees Celsius?
Brut [27]

Answer:-

2328.454 grams

Explanation:-

Volume V = 18.4 litres

Temperature T = 15 C + 273 = 288 K

Pressure P = 1.5 x 10^ 3 KPa

We know universal Gas constant R = 8.314 L KPa K-1 mol-1

Using the relation PV = nRT

Number of moles of oxygen gas n = PV / RT

Plugging in the values

n = (1.5 x 10^3 KPa ) x ( 18.4 litres ) / ( 8.314 L KPa K-1 mol-1 x 288 K)

n = 11.527 mol

Now the balanced chemical equation for this reaction is

2KNO3 --> 2KNO2 + O2

From the equation we can see that

1 mol of O2 is produced from 2 mol of KNO3.

∴ 11.527 mol of O2 is produced from 2 x 11.527 mol of KNO3.

= 23.054 mol of KNO3

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= 2328.454 grams

7 0
3 years ago
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