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What is the ratio of effusion rates for the lightest gas, h2, to the heaviest known gas, uf6?

andriy [413]

The ratio of effusion rates for the lightest gas H₂ to the heaviest known gas UF₆ is 13.21 to 1

<h3>What is effusion?</h3>

Effusion is a process by which a gas escapes from its container through a tiny hole into evacuated space.

Rate of effusion ∝ 1/√Ц, (where Ц is molar mass)

Rate H₂ = 1/√ЦH₂

Rate UF₆ = 1/√ЦUF₆

Therefore, Rate H₂/ Rate UF₆ = √ЦH₂/√ЦUF₆

ЦH₂= 2.016 g/mol

ЦUF₆= 352.04 g/mol

Rate H₂ / Rate UF₆ = √352.04/√2.016 = 18.76/1.42

Rate H₂ / Rate UF₆ = 13.21

Therefore, H₂ is lower mass than UF₆. Thus H₂ gas will effuse 13 times more faster than UF₆ because the most probable speed of H₂ molecule is higher; therefore, more molecules escapes per unit time.

learn more about effusion rate: brainly.com/question/28371955

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8 0

1 year ago

Why do organisms need nitrogen?

RSB [31]

All bulbs/plants and creatures want nitrogen to produce amino hallucinogen, proteid and DNA, although this nitrogen in the air is not in a manner that everybody can use.

For more information, look at the appendage below!

6 0

3 years ago

Why does the sun move from night-time to dayime?

valentina_108 [34]

Answer: Rotation cause by the earths orbit and gravity

Explanation:

4 0

2 years ago

Read 2 more answers

How much heat is required to change the temperature of 100 grams of water from 25 to 55oc?

marysya [2.9K]

Hthe heat required to change the temperfature of 100 grams of water from 25 to 55 c is calculated as below

Q(heat) = M(mass) x C(specific heat capacity) x delta T(change in temperature)

M= 100 grams
C= 4.18 j/g/c
delta T= 55-25 =30c

Q=100 g x4.814 j/g/c x 30c = 12552 joules

5 0

3 years ago

Please help !!

ipn [44]

Answer:

For 2: The % yield of the product is 92.34 %

For 3: 12.208 L of carbon dioxide will be formed.

Explanation:

For 2:

The percent yield of a reaction is calculated by using an equation:

$\% \text{yield}=\frac{\text{Actual value}}{\text{Theoretical value}}\times 100$ ......(1)

Given values:

Actual value of the product = 78.4 g

Theoretical value of the product = 84.9 g

Plugging values in equation 1:

$\% \text{yield}=\frac{78.4 g}{84.9g}\times 100\\\\\% \text{yield}=92.34\%$

Hence, the % yield of the product is 92.34 %

For 3:

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(2)

Given mass of carbon dioxide = 24 g

Molar mass of carbon dioxide = 44 g/mol

Plugging values in equation 1:

$\text{Moles of carbon dioxide}=\frac{24g}{44g/mol}=0.545 mol$

At STP conditions:

1 mole of a gas occupies 22.4 L of volume

So, 0.545 moles of carbon dioxide will occupy = $\frac{22.4L}{1mol}\times 0.545mol=12.208L$ of volume

Hence, 12.208 L of carbon dioxide will be formed.

5 0

3 years ago