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Rus_ich [418]
3 years ago
10

A compound contains only carbon, hydrogen, nitrogen, and oxygen. Combustion of 0.157 g of the compound produced 0.213 g of CO2 a

nd 0.0310 g of H2O. In an- other experiment, 0.103 g of the compound produced 0.0230 g of NH3. What is the empirical formula of the compound? Hint: Combustion involves reacting with ex- cess O2. Assume that all the carbon ends up in CO2 and all the hydrogen ends up in H2O. Also assume that all the nitrogen ends up in the NH3 in the second experiment.
Chemistry
1 answer:
Alex_Xolod [135]3 years ago
8 0

Answer:

hkvh

Explanation:

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Black holes are so dense that light cannot escape from them, and they are difficult to detect. Satellites above the Earth's atmosphere can detect bursts of high energy radiation given off by black holes. Dozens of stellar black holes have already been detected in the Milky Way, where there may be tens of millions more.

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4 0
3 years ago
If the pressure on a gas is increased, then its volume will...?
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Decrease. I got you

4 0
4 years ago
The industrial solvent carbon disulfide (CS2) is produced when coke (C) and sulfur dioxide (SO2) react. If 8.00 g of SO2 reacts,
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Answer:

0.0624 mol

Explanation:

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7 0
2 years ago
Total and net ionic equation of 2FeCl3(aq)+ 3Mg(NO3)2 (aq)----> 3MgCl2(aq) + 2Fe(NO3)3(aq)
enot [183]
Write balanced molecular, ionic, and net ionic equations<span> (NIE) for each of the ... </span>3.Mg(OH)2(aq) +. 2HCl(aq). →. MgCl2(aq). +. 2H2O(l). Ionic Equation: Mg2+(aq). + ... 2-(aq). +. Ca2+(aq). →. Ca(C2O4)(s). 5. 2(NH4)3PO4(aq) +. 3Zn(NO3)2(aq) → ... 2-(aq<span>). →. MgCrO4(s). 9. </span>2FeCl3(aq<span>). +. </span>3Mg<span>(s). →. </span>3MgCl2(aq<span>) +. </span>2Fe<span>(s).</span>
6 0
3 years ago
Calculate the molarity of each solution. 28.33 g c6h12o6 in 1.28 l of solution
QveST [7]
Molarity is number of moles of solute in 1 L of solution
number of moles of glucose  -28.33 g / 180 g/mol  = 0.1574 mol 
volume of solution is 1.28  L
since molarity is number of moles in 1 L
the number of moles in 1.28 L - 0.1574 mol
therefore number of moles in 1 L - 0.1574 mol / 1.28 L = 0.123 M
molarity is 0.123 M

4 0
3 years ago
Read 2 more answers
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