Answer: The initial temperature of the iron was
Explanation:
As we know that,
.................(1)
where,
q = heat absorbed or released
= mass of iron = 360 g
= mass of water = 750 g
= final temperature =
= temperature of iron = ?
= temperature of water =
= specific heat of iron =
= specific heat of water=
Now put all the given values in equation (1), we get
Therefore, the initial temperature of the iron was
Answer:
Explanation:
Any gas at standard temperature and pressure (STP) has a volume of 22.4 liters per mole or 22.4 L/mol. We can create a proportion with this value.
Multiply both sides of the equation by 6.8 moles of krypton.
The units of moles of krypton will cancel.
The denominator of 1 can be ignored, so this becomes a simple multiplication problem.
If we round to the nearest whole number, the 3 in the tenths place tells us to leave the 2 in the ones place.
6.8 moles of krypton gas at standard temperature and pressure is equal to <u>152 liters</u>.