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3 years ago

A disturbance sends ripples across water in a tub.

Physics

2 answers:

nataly862011 [7]3 years ago

5 0

Answer:

Option (1)

Explanation:

Ripples (ripple marks) are formed due to the forward and backward motion of water over the surface of a rock bed or water bodies. They are usually formed when the flow velocity is less and the diameter of the grains is relatively small.

These are sedimentary structures that are found in many places. These ripples are divided into 2 types, namely the symmetric and the asymmetric ripples. Asymmetrical ripples are helpful in identifying the palaeocurrent direction.

These are formed when water travels over the surface, so <u>it can be considered as the surface waves. </u>

Hence, the most appropriate answer is option (1).

Alex787 [66]3 years ago

3 0

I believe it is surface waves because it happens at the surface of the water.

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The potential-energy function u(x) is zero in the interval 0≤x≤l and has the constant value u0 everywhere outside this interval.

VMariaS [17]

Look first for the relation between deBroglie wavelength (λ) and kinetic energy (K):
K = ½mv²
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λ = h/(mv)
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So λ is proportional to 1/√K.
in the potential well the potential energy is zero, so completely the electron's energy is in the shape of kinetic energy:
K = 6U₀

Outer the potential well the potential energy is U₀, so
K = 5U₀
(because kinetic and potential energies add up to 6U₀)

Therefore, the ratio of the de Broglie wavelength of the electron in the region x>L (outside the well) to the wavelength for 0<x<L (inside the well) is:
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3 years ago

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Stolb23 [73]

Answer:

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A hill that has a 15.5% grade is one that rises 15.5 m vertically for every 100.0 m of distance in the horizontal direction. At

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The angle of incline of the hill above the horizontal is 8.81°.

Since the hill has a 15.5% grade is one that rises 15.5 m vertically for every 100.0 m of distance in the horizontal direction.

<h3>Tangent of the angle of the incline of the hill,</h3>

The tangent of the angle of the incline of the hill, Ф is

tanФ = vertical rise/horizontal distance = grade of hill

Now, the vertical rise = 15.5 m and the horizontal distance = 100.0 m

So, substituting the values of the variables into the equation, we have

tanФ = vertical rise/horizontal run

tanФ = 15.5 m/100.0 m

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<h3>Angle of incline of the hill</h3>

Taking inverse tan of both sides, we have

Ф = tan⁻¹(0.155)

Ф = 8.81°

So, the angle of incline of the hill above the horizontal is 8.81°.

Learn more about angle of incline of a hill here:

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