Answer:
The induced current in the loop is 1.2 A
Explanation:
Given;
length of the wire, L = 24 cm = 0.24 m
resistance of the wire, R = 0.14 Ω.
magnetic field strength, B = 0.55 T
time, t = 15 ms = 15 x 10⁻³ s
Circumference of a circle is given as;
L = 2πr
0.24 = 2πr
r = 0.24 / 2π
r = 0.0382 m
Area of a loop is given as;
A = πr²
A = π (0.0382)²
A = 0.004585 m²
Induced emf is given as;
Ф = ΔB x A
Ф = ( 0 - 0.55 T) x 0.004585 m²
Ф = -0.002522 T.m²
According to ohm's law;
V = IR
Where;
I is current
The induced current in the loop is calculated as;
I = V / R
I = 0.168 / 0.14
I = 1.2 A
Therefore, the induced current in the loop is 1.2 A