The classical physics works on the Newton's laws of motion. It is applicable on heavenly bodies which are governed by the gravitational force. On the other hand, Quantum Physics is applicable for very low mass and sized bodies like electron, protons etc. The classical physics would accurately describe the motion of satellite moving with speed 7500 m/s using the following formula:
where G is the gravitational constant, M is the mass of the planet and v is the orbital speed. Then radius of the orbit can be described by this formula.
<h3><u>Answer;</u></h3>
Transmission
<h3><u>Explanation;</u></h3>
- <em><u>Light waves are types of waves that are electromagnetic waves, meaning they do not require material medium for transmission. </u></em>Light is transmitted as a transverse wave such that the vibration of particles is perpendicular to the direction of wave motion.
- <em><u>A material medium enables the transmission of a wave by the vibration of particles, atoms or molecules. </u></em>The vibration of particles in a medium helps in the transmission of a wave such that energy is transferred from one point to another due to the disturbance caused by the wave.
0.9 is less than 1.0 by 0.1
so your answer is true
hope this helps
Answer:
Explanation:
<u>Center of Gravity
</u>
It refers to a point where all the forces of gravity of a body make a zero total torque. To find the solution we use the fact that the net force acting on the system boat-man is in every moment equal to zero. It's assured by the first Newton’s law, the center of gravity is at rest or in uniform motion in both moments. From an external viewer's point of view, the center of gravity remains unchanged. The formula to compute it is shown below
Originally, the man sits on the stern of the boat. His weight is applied at a distance xm=4.9 m from the pier (assumed as x=0). The boat is assumed to have a uniformly distributed mass applied at its center, i.e. at xb = 4.9 / 2 = 2.45 m. The center of gravity is located originally at
When the man walks to the prow, the boat moves x = 1.2 m from the pier, so its center is located at a distance
The man is located at
The center of gravity is computed now as
Both centers of gravity are equal, thus
Simplifying
Rearranging
Thus
Answer:
5.9 cm
Explanation:
We'll begin by calculating the spring constant (K) of the spring. This can be obtained as follow:
Force (F) = 15 N
Extention (e) = 3 cm
Spring constant (K) =.?
F = Ke
15 = K × 3
Divide both side by 3
K = 15 / 3
K = 5 N/cm
Therefore, the spring constant (K) is 5 N/cm.
Now, we shall determine how far the spring will stretch when a 3 kg candy is placed on the spring balance.
This can be obtained as follow:
First, we shall determine the weight of the object.
Mass of object = 3 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Weight (W) =?
W = mg
W = 3 × 9.8
W = 29.4 N
Finally, we shall determine how far the spring will stretch as follow:
Weight (W) = Force (F) = 29.4 N
Spring constant (K) = 5 N/cm
Extention (e) =?
F = ke
29.4 = 5 × e
Divide both side by 5
e = 29.4 / 5
e = 5.88 ≈ 5.9 cm
Therefore, the spring will stretch 5.9 cm when a 3 kg candy is placed on the spring balance.
