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3 years ago

6

Help Help Help Explain how Newton’s Laws apply to traveling to and landing on Mars.

1 answer:

Ganezh [65]3 years ago

5 0

Answer:

Newton deduced that when one object exerted force upon a second object, that second object exerted an equal and opposite force on the first one. This law explains how the sun pulls on planets with gravity, just as the planets pull on the sun. Newton's last law describes how gravity works.

Explanation:

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☆ Correct and rewrite the following statements:

kvv77 [185]

Answer:

<h3>e)</h3><h3><u>Question</u><u>:</u><u>-</u></h3>

Electroplating is based on magnetic effect of electricity.

<h3><u>Answer</u><u>:</u><u>-</u></h3>

<em>It's</em><em> </em><em>incorrect</em><em> </em><em>sentence</em><em> </em>
As we know that, while electroplating there are two rods, one becoming cathode and another one becoming anode. During electroplating, when electricity is given through the rods, the anode produces positive ions which gets received at the cathode rod and negative ions produced at cathode collects at anode rod which results to the plating of the desired substance. Here, it is a chemical effect of electricity resulting to plating.

<u>So correct sentence is:</u>

<em>Electroplating</em><em> </em><em>is</em><em> </em><em>based</em><em> </em><em>of</em><em> </em><em>chemical</em><em> </em><em>effect</em><em> </em><em>of</em><em> </em><em>electricity</em><em>.</em><em> </em>

<h3>f)</h3><h3><u>Question</u><u>:</u><u>-</u></h3>

An electric bulb glows due to the chemical effect of electricity.

<h3><u>Answer</u><u>:</u><u>-</u></h3>

<em>It's</em><em> </em><em>incorrect</em><em> </em><em>sentence</em><em> </em>
As we know that, in an electric bulb there is a filament. When electricity is given in that filament of the electric bulb, the filament gets intensely heated up and results to the emission of light. Due to this heating of the filament due to electricity the electric bulb glows.

<u>So correct sentence is:</u>

<em>A</em><em>n electric bulb glows due to the </em><em>h</em><em>e</em><em>a</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>effect of electricity.</em>

6 0

2 years ago

A basketball player of height 2.40 m is standing 2.60 m in front of a convex spherical mirror of radius of curvature 4.00 m. Det

IrinaVladis [17]

Answer:

The size of the image is 1.04 m.

Explanation:

Given that,

Height of object = 2.40 m

Distance of object = 2.60 m

Radius of curvature =4.00 m

Focal length $f=\dfrac{R}{2}=\dfrac{4.00}{2}=2.00$

We need to calculate the image distance

Using mirror formula

$\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}$

$\dfrac{1}{v}=\dfrac{1}{2.00}+\dfrac{1}{2.60}$

$\dfrac{1}{v}= \dfrac{23}{26}$

$v=1.13\ cm$

We need to calculate the height of the image

Using formula of magnification

$m=\dfrac{h'}{h}=-\dfrac{v}{u}$

Put the value into the formula

$\dfrac{h'}{2.40}=-\dfrac{1.13}{-2.60}$

$h'=\dfrac{1.13}{2.60}\times2.40$

$h'=1.04\ m$

Hence, The size of the image is 1.04 m

8 0

3 years ago

The mass of _______ makes up 70 percent of all planetary mass in the solar system. A. Uranus B. Neptune C. Jupiter D. Saturn

yawa3891 [41]

C. Jupiter's mass is the largest

4 0

3 years ago

Read 2 more answers

Drag the tiles to the boxes to form correct pairs. The table shows the distances between a star and three celestial objects. Use

aliina [53]

Answer:

Explanations :

4 1

3 years ago

A river flows with a uniform velocity vr. A person in a motorboat travels 1.22 km upstream, at which time she passes a log float

storchak [24]

Answer:

t ’= $\frac{1450}{0.6499 + 2 v_r}$ , v_r = 1 m/s t ’= 547.19 s

Explanation:

This is a relative velocity exercise in a dimesion, since the river and the boat are going in the same direction.

By the time the boat goes up the river

v_b - v_r = d / t

By the time the boat goes down the river

v_b + v_r = d '/ t'

let's subtract the equations

2 v_r = d ’/ t’ - d / t

d ’/ t’ = 2v_r + d / t

$t' = \frac{d'}{ \frac{d}{t}+ 2 v_r }$

In the exercise they tell us

d = 1.22 +1.45 = 2.67 km= 2.67 10³ m

d ’= 1.45 km= 1.45 1.³ m

at time t = 69.1 min (60 s / 1min) = 4146 s

the speed of river is v_r

t ’= $\frac{1.45 \ 10^3}{ \frac{ 2670}{4146} \ + 2 \ v_r}$

t ’= $\frac{1450}{0.6499 + 2 v_r}$

In order to complete the calculation, we must assume a river speed

v_r = 1 m / s

let's calculate

t ’= $\frac{ 1450}{ 0.6499 + 2 \ 1}$

t ’= 547.19 s

8 0

3 years ago