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3 years ago

Sodium chloride is an ionic compound. If you drop a large crystal of sodium chloride on a hard floor. Choices are change to gas,

Chemistry

1 answer:

natita [175]3 years ago

3 0

Shatter into tiny pieces

The crystal may break due to the fall.

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Regular table salt is sodium chloride, NaCl. It is a bonding of an Na+ ion and a Cl- ion. Which of these ions is bigger?

fenix001 [56]

Answer:

in the periodic table we can see that the ions of Cl is greater than the ions in Na

3 0

2 years ago

How many half-lives will pass by the time 1.56% of I-131 is present? B. Approximately how many days does that equal? *

serg [7]

Answer: Hmmmmm that's crazy....

There are a couple of equations one could use for this type of problem, but I find the following to be the easiest to use and to understand.

Fraction remaining (FR) = 0.5n

n = number of half lives that have elapsed

In this problem, we need to find n and are given the FR, which is 1.56% or 0.0156 (as a fraction).

0.0156 = 0.5n

log 0.0156 = n log 0.5

-1.81 = -0.301 n

n = 6.0 half lives have elapsed

Explanation:

Just wanted to help. Hopefully it's correct wouldn't want to waster your time ;)

6 0

2 years ago

What is the ratio of Al 3+ ions to S 2- ions in a neutral compound?

iren2701 [21]

In a neutral ionic compound, you can determine its sub-scripts by simply flipping the ionic charges and dropping the signs: so AlS would be Al2S3

4 0

3 years ago

Read 2 more answers

g Five calcite, CaCO3 (MW 100.085 g/mol), samples of equal mass have a total mass of 12.3±0.1 g. What is the absolute uncertaint

diamong [38]

Answer:

The value is $L = 0.985 \pm 0.00801 \ g$

Explanation:

From the question we are told that

The molar mass of $CaCO_3$ is $MW = 100.085 \ g/mol$

The total mass is $m_g = 12.3 \ g$

The uncertainty of the total mass is $\Delta g = 0.1$

Generally the molar weight of calcium is $M_c = 40 g/mol$

The percentage of calcium in calcite is mathematically represented as

$C = \frac{40.07}{100.085} * 100$

$C = 40.03 \%$

Generally the mass of each sample is mathematically represented as

$m= \frac{m_g}{5}$

$m= \frac{12.3}{5}$

$m= 2.46 \ g$

Generally mass of calcium present in a single sample is mathematically represented as

$m_c = 2.46 * \frac{40.04}{100}$

$m_c = 0.985 \ g$

The uncertainty of mass of a single sample is mathematically represented as

$k = \frac{\Delta g }{5}$

$k = \frac{0.1 }{5}$

$k = 0.02\ g$

The uncertainty of mass of calcium in a single sample is mathematically represent

$G = \frac{0.02 * 40.04}{ 100}$

$G = 0.00801 \ g$

Generally the average mass of calcium in each sample is

$L = 0.985 \pm 0.00801$

6 0

2 years ago

The acceleration of a runner who accelerates from 0 m/s to 3 m/s in 12s

Naily [24]

4 m/s^2

I hope this helps!

5 0

3 years ago