Mechanical waves need mediums. or else it isn't a mechanical wave
Given the molarity of the solution is
.
The volume of the solution is 10.9/1000 L
Number of moles of HCl = Molarity * volume of the solution in L
Number of moles of HCl =*
Number of moles of HCl = 2.7 moles.
Therefore number of moles of HCl in 10.9 ml of the stomach acid is 2.7 moles
To get the melting point of a solution so, we will use this formula:
ΔT = - mKf
when:
m is molality of the solution
Kf is cryoscopic constant of water = 1.86 C/m
and ΔT is the change in melting point (T2 - 0 °C)
so, now we need to calculate the molality to substitute:
when the molality = moles NaCl / Kg of water
and when moles NaCl = mass / molar mass
= 2.5 g / 58 g/mol
= 0.043 mol
∴ Kg water = volume *density /1000
= 230 mL * 1 g/mL / 1000
= 0.23 Kg
∴ molality = 0.043 / 0.23 =0.187 M
by substitution:
T2-0°C = - 0.187 * 1.86
∴T2 = - 0.348 °C
Use ideal gas law PV=nRT
Convert 5.00 atm to kPa since units must be relative to gas constant (r).
To do this multiply 5 by 101.03 (1 atm=101.3kPa)
Now plug in (506.5kPa)(10.0L)=n(8.31 L•atm/mol•K)(373K)
Solve for n (moles) to get approximately 1.634 mol. Now use dimensional analysis (1.634mol/1)(22.4L/1mol) = 36.6L
Answer:
6.05 g
Explanation:
Molarity of a substance , is the number of moles present in a liter of solution .
M = n / V
M = molarity
V = volume of solution in liter ,
n = moles of solute ,
From the question ,
M = 200mM
Since,
1 mM = 10⁻³ M
M = 200 * 10⁻³ M
V = 250 mL
Since,
1 mL = 10⁻³ L
V = 250 * 10⁻³ L
The moles can be calculated , by using the above relation,
M = n / V
Putting the respective values ,
200 * 10⁻³ M = n / 250 * 10⁻³ L
n = 0.05 mol
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = w / m
n = moles ,
w = given mass ,
m = molecular mass .
From the question ,
m = 121 g/mol
n = 0.05 mol ( calculated above )
The mass of tri base can be calculated by using the above equation ,
n = w / m
Putting the respective values ,
0.05 mol = w / 121 g/mol
w = 0.05 mol * 121 g/mol
w = 6.05 g
