Question

NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. A 60-kg pilot flies a jet trainer in a half vertical loop of 1200-m radius so that the speed of the trainer decreases at a constant rate. Know that the plane has a speed of 550 km/h at point A, and the pilot experiences weightlessness at point C (i.e., the normal force from the seat bottom is zero). Determine the deceleration of the plane. (You must provide an answer before moving on to the next part.) The deceleration of the plane is m/s2.

Answer 1

Answer:

-  4.88 m/ s²

Explanation:

Speed of trainer = 550 km/h

= 152.77 m /s

For making apparent weight equal to zero, weight must be equal to centrifugal force or

mg = mv² / R

g = v² / R

v² = gR

= 9.8 x 1200

= 11760

v = 108.44 / m

So velocity has to be reduced from 152.77 to 108.44 m /s

Distance covered during this period

= 2πR / 4 = 2 x3.14 x 1200 / 4

= 1184 m

v² - u² = 2as

108.44² - 152.77² = 2x a x 1184

a = -  4.88 m/ s²