NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. A 60-kg pilot flies
1 answer:
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Answer:
24.71cm
Explanation:
We approach this problem base don Hooke's law which states the elongation produced in an elastic material is proportional to the applied load or force provided that its elastic limit is not exceeded. This is expressed mathematically as follows;
where F is the applied force, k is the force constant and e is the elongation or extension of the material.
In this problem, the applied force F is the weight of the wood which is calculated as follows,
m = 4.11kg
Hence,
Given that k = 163N/m, we make appropriate substitutions into equation (1) to obtain the following;
Since it is required in cm, we perform the conversion as follows, knowing that 100cm = 1m
NB: We do not necessarily need the the density of the wood to perform our calculations since other parameters were given from which we were able to obtain its weight.
Answer:
v_y = 14.55 m/s
Explanation:
given,
height at which gull is flying = 10.80 m
speed of the gull = 6 m/s
acceleration due to gravity = 9.8 m/s²
Relative to the seagull, the x-speed is 0,
because the seagull has the same x-speed.
Only the y-speed counts:
v_y = 14.55 m/s
hence, the speed at which the clam smash the rock is v_y = 14.55 m/s