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Otrada [13]
2 years ago
8

Which statement is true about magnetic poles? Question 20 options: all magnets have two poles Any magnet can have two north pole

s. Any magnet has only one pole. Any magnet can have two south poles.
Physics
1 answer:
irga5000 [103]2 years ago
5 0

Every magnet consists of two poles one is the south pole other one is the north pole. All magnets have two poles. This statement is correct.

<h3>What are magnetic poles?</h3>

The area at either end of a magnet where the external magnetic field is strongest is known as a magnetic pole.

Every magnet consists of two poles one is the south pole other one is the north pole like poles attracts each other while unlike poles repel each other.

Hence option (a) is correct. All magnets have two poles.

To learn more about the magnetic poles refer to the link;

brainly.com/question/1377848

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Answer:B

Explanation:

.03 of an hr is 2 mins and if it takes 2 mins to drive 4 miles enter it in pace calulator you are going 120mph so the closest to 120 is 133mph

7 0
3 years ago
A sound wave has a frequency of 295 Hz and travels the length of a football field, 91.4 m in 0.506 s. What is the period of the
dem82 [27]

Answer:1/295 seconds

Explanation:

Period=1/frequency

Period=1/295 seconds

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In what state of matter does oxygen exist at room temperature
denis-greek [22]
Oxygen is a gas a room temperature.


4 0
3 years ago
Read 2 more answers
PLEASE HELP!!!!!
never [62]

Answer:

The answer is A

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When a rockets thrusters push on the ground the ground pushes back on the rocket with equal force in the opposite direction. Hence the rocket takes off.

Newtons third law of motion states, for every action there is an equal and opposite reaction.

7 0
2 years ago
Argon gas enters steadily an adiabatic turbine at 900 kPa and 450C with a velocity of 80 m/s and leaves at 150 kPa with a veloc
Crazy boy [7]

Answer:

Temperature at the exit = 267.3 C

Explanation:

For the steady energy flow through a control volume, the power output is given as

W_{out}= -m_{f}(h_{2}-h_{1} + \frac{v_{2}^{2}}{2} - \frac{v_{1}^{2}}{2})

Inlet area of the turbine = 60cm^{2}= 0.006m^{2}

To find the mass flow rate, we can apply the ideal gas laws to estimate the specific volume, from there we can get the mass flow rate.

Assuming Argon behaves as an Ideal gas, we have the specific volume v_{1}

as

v_{1}=\frac{RT_{1}}{P_{1}}=\frac{0.2081\times723}{900}=0.1672m^{3}/kg

m_{f}=\frac{1}{v_{1}}\times A_{1}V_{1} = \frac{1}{0.1672}\times(0.006)(80)=2.871kg/sec

for Ideal gasses, the enthalpy change can be calculated using the formula

h_{2}-h_{1}=C_{p}(T_{2}-T_{1})

hence we have

W_{out}= -m_{f}((C_{p}(T_{2}-T_{1}) + \frac{v_{2}^{2}}{2} - \frac{v_{1}^{2}}{2})

250= -2.871((0.5203(T_{2}-450) + \frac{150^{2}}{2\times 1000} - \frac{80^{2}}{2\times 1000})

<em>Note: to convert the Kinetic energy term to kilojoules, it was multiplied by 1000</em>

evaluating the above equation, we have T_{2}=267.3C

Hence, the temperature at the exit = 267.3 C

5 0
3 years ago
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