The pattern of weather in an area overtime is called
1 answer:
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Answer:
10.86 N
Explanation:
Let the average frictional force acting on the toboggan be 'f' N.
Given:
Mass of toboggan (m) = 19.0 kg
Initial velocity (u) = 4.00 m/s
Final velocity (v) = 0 m/s
Time for which friction acts (Δt) = 7.00 s
Now, change in momentum is given as:
Now, we know that, change in momentum is equal to the impulse acting on the body. So,
Impulse is,
Now, we know that, impulse is also given as the product of average force and the time interval for which it acts. So,
Rewriting the above equation in terms of 'f', we get:
Plug in the given values and solve for 'f'. This gives,
Therefore, the magnitude of frictional force is
Answer:
-22.2 m/s²
Explanation:
The equation for position x for a constant acceleration a, time t and initial velocity v₀, initial position x₀:
(1)
For rocket A the initial and final position: x = x₀= 0. Using these values in equation 1 gives:
(2)
Solving for time t:
(3)
The times for both rockets must be equal, since they start and end at the same location. Using equation 3 for rocket A and B gives:
(4)
Solving equation 4 for acceleration of rocket B:
(5)